An 65.73 g sample of aluminum is placed on a 56.35 g sample of copper initially...

An 65.73 g sample of aluminum is placed on a 56.35 g sample of copper initially at 111.86^oC. If the heat is only transferred between the metals (with no loss to the surroundings) and the final temperature of both metals is 36.38^oC, what is the inital temperature (in ^oC) of aluminum?

Expert Solution

Heat lose of Cu = Heat gain of Al

mcT = mcT

56.35*0.385*(111.86-36.38) = 65.73*0.902*(36.38-t)

t = 8.37⁰C

The initial temperature of Al = 8.37⁰C

queen_honey_blossom answered 2 years ago

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