Question

In: Statistics and Probability

4. An airline wants to know the impact of method of redeeming frequent-flyer miles and the...

4. An airline wants to know the impact of method of redeeming frequent-flyer miles and the age group of customers on how the number of miles they redeemed. To do so, they perform a two-way analysis of variance on the data for miles redeemed shown on cells L35 to O43 on the answers sheet.
a. Identify the null and alternative hypotheses for each of the two main effects and the interaction.
b. Use two-way analysis of variance to test each of these three sets of hypotheses at the 0.05 significance level.
Customer age ranges
Methods of redeeming miles Under 25 25 to 40 41 to 60 Over 60
Cash 300,000 60,000 40,000 0
0 0 25,000 5,000
25,000 0 25,000 25,000
Discount Vacations 40,000 40,000 25,000 45,000
25,000 25,000 50,000 25,000
0 5,000 0 0
Discount Internet Shopping Spree 25,000 30,000 25,000 30,000
25,000 25,000 50,000 25,000
75,000 50,000 0 25,000
b. SS df MS Fcalc Fcrit p-value
Methods of redeeming miles Reject H0or not? α = 0.05
Customer age ranges Reject H0or not? α = 0.05
Interaction Reject H0or not? α = 0.05
Error

Solutions

Expert Solution

Hypothesis 1

H0 : The mean number of miles redeemed is the same across age groups
H1 : The mean number of miles redeemed is not the same across age groups

Hypothesis 2
H0 : The mean number of miles redeemed is the same for all the three methods of redeeming miles
H1 : The mean number of miles redeemed is not the same for all the three methods of redeeming miles

Hypothesis 3

H0 : There in no interaction between the age group and the method of redeeming.
H1: There in an interaction between the age group and the method of redeeming.

2 ways anova in excel.

1. Input the data in excel as shown


2. Under the data tab, select the data analysis and select
two way anova with replication.


3. Update the input in the dialogue box


4. The output is generated as follows.

We use the pvalue for testing the hypothesis. (Highlighted in yellow).
Also the next to the
anova output is have indicated which pvalue correspond to which variable.

Methods of redeeming miles
Here the pvalue 0.65 is greater than 0.05, hence we fail to reject the null hypothesis and conclude that the mean number of miles redeemed is the same for all the three methods of redeeming miles

Age group
Here the pvalue 0.74 is greater than 0.05, hence we fail to reject the null hypothesis and conclude that the mean number of miles redeemed is the same for all the three methods of redeeming miles

Interaction
Here the pvalue 0.85 is greater than 0.05, hence we fail to reject the null hypothesis and conclude that there in no interaction between the age group and the method of redeeming.


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