In: Statistics and Probability
1. Two samples are taken with the following sample means, sizes, and standard deviations
¯x1 = 31 ¯x2 = 35
n1= 73   n2= 67
s1= 2 s2 = 5
Estimate the difference in population means using a 99% confidence
level. Use a calculator, and do NOT pool the sample variances.
Round answers to the nearest hundredth.
_____< μ1−μ2 <_____
2. You are conducting a test of independence for the claim that there is an association between the row variable and the column variable.
| X | Y | Z | |
|---|---|---|---|
| A | 27 | 33 | 48 | 
| B | 12 | 35 | 46 | 
What is the chi-square test-statistic for this data? Round to 3
decimal places
χ2=_____
3. You are conducting a test of homogeneity for the claim that two different populations have the same proportions of the following two characteristics. Here is the sample data.
| Category | Population #1  | 
Population #2  | 
|---|---|---|
| A | 6 | 6 | 
| B | 52 | 51 | 
What is the chi-square test-statistic for this data? Report to 3
decimal places
χ2=______
1)
The confidence interval for difference in means is obtained using the formula,

Where,

The degree of freedom is obtained using the formula,


The t critical value is obtained from t distribution table for significance level = 0.01 and degree of freedom = 85.12




2)
The observed values are,
| Observed values | ||||
| X | Y | Z | Total | |
| A | 27 | 33 | 48 | 108 | 
| B | 12 | 35 | 46 | 93 | 
| Total | 39 | 68 | 94 | 201 | 
The expected values are obtained using the formula,

| Expected values | ||||
| X | Y | Z | Total | |
| A | 
![]()  | 
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108 | 
| B | 
![]()  | 
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93 | 
| Total | 39 | 68 | 94 | 201 | 
The Chi-Square Value is obtained using the formula

Observed, ![]()  | 
Expected, ![]()  | 
![]()  | 
![]()  | 
![]()  | 
| 27 | 20.96 | 6.04 | 36.54 | 1.74 | 
| 33 | 36.54 | -3.54 | 12.51 | 0.34 | 
| 48 | 50.51 | -2.51 | 6.29 | 0.12 | 
| 12 | 18.04 | -6.04 | 36.54 | 2.02 | 
| 35 | 31.46 | 3.54 | 12.51 | 0.40 | 
| 46 | 43.49 | 2.51 | 6.29 | 0.14 | 
| 4.778 | 

3)
The chi-square test for homogeneity can be used here to determine whether the several populations are equal or homogeneous in some characteristics
he Chi-Square test statistic is obtained as follow,
The observed values are,
| Observed values | |||
| Population 1 | Population 2 | Total | |
| A | 6 | 6 | 12 | 
| B | 52 | 51 | 103 | 
| Total | 58 | 57 | 115 | 
The expected values are obtained using the formula,

| Expected values | |||
| X | Y | Total | |
| A | 6.05 | 5.95 | 12 | 
| B | 51.95 | 51.05 | 103 | 
| Total | 58 | 57 | 115 | 
The Chi-Square Value is obtained using the formula

  | 
Expected, ![]()  | 
![]()  | 
![]()  | 
![]()  | 
|
| 6 | 6.0522 | -0.0522 | 0.0027 | 0.0004 | |
| 6 | 5.9478 | 0.0522 | 0.0027 | 0.0005 | |
| 52 | 51.9478 | 0.0522 | 0.0027 | 0.0001 | |
| 51 | 51.0522 | -0.0522 | 0.0027 | 0.0001 | |
| 0.001 | 
