In: Math
Here,
Sample mean \(=\bar{x}=5.88\)
Sample \(S . D=s=2.06\)
Sample size \(=n=195\)
Degrees of freedom \(=194\)
Significance Level \(=\alpha=0.05\)
Step 1: \(H_{0}: \mu=6\)
\(H_{1}: \mu<6\) (Left tailed test)
Step 2: The test statistic is, \(t=\frac{\bar{x}-\mu}{\left(\frac{s}{\sqrt{n}}\right)}=-0.81\)
Step \(3: P-\) value \(=P(t<-0.81)=0.209\)
Step \(4:\) We fail to reject \(H_{0} .\) There is not sufficient evidence to conclude that the mean of the population of ratings is less than \(6.00\).