In: Math
A food company has developed a high mineral sea salt (sodium). A
nurse practitioner wants to know if blood pressure can be predicted
from the sodium intake of the new sea salt. Below are the sodium
and BP measurements for a sample of participants that regularly use
the new sea salt. What can the nurse practitioner conclude with α =
0.01?
Sodium | BP |
---|---|
8.3 8.2 8.3 8.2 8.4 8.4 8.3 8.2 8.3 |
167 146 190 187 149 141 145 190 175 |
a) What is the appropriate statistic?
---Select--- na Correlation Slope Chi-Square
Compute the statistic selected a):
b) Compute the appropriate test statistic(s) to
make a decision about H0.
(Hint: Make sure to write down the null and alternative hypotheses
to help solve the problem.)
Critical value = ; Test statistic =
Decision: ---Select--- Reject H0 Fail to reject H0
c) Compute the corresponding effect size(s) and
indicate magnitude(s).
If not appropriate, input and/or select "na" below.
Effect size = ; ---Select--- na trivial
effect small effect medium effect large effect
d) Make an interpretation based on the
results.
More sodium intake significantly predicts an increase in blood pressure.More sodium intake significantly predicts a decrease in blood pressure. Sodium intake does not significantly predict blood pressure.
X | Y | XY | X² | Y² |
8.3 | 167 | 1386.1 | 68.89 | 27889 |
8.2 | 146 | 1197.2 | 67.24 | 21316 |
8.3 | 190 | 1577 | 68.89 | 36100 |
8.2 | 187 | 1533.4 | 67.24 | 34969 |
8.4 | 149 | 1251.6 | 70.56 | 22201 |
8.4 | 141 | 1184.4 | 70.56 | 19881 |
8.3 | 145 | 1203.5 | 68.89 | 21025 |
8.2 | 190 | 1558 | 67.24 | 36100 |
8.3 | 175 | 1452.5 | 68.89 | 30625 |
Ʃx = | Ʃy = | Ʃxy = | Ʃx² = | Ʃy² = |
74.6 | 1490 | 12343.7 | 618.4 | 250106 |
Sample size, n = | 9 |
x̅ = Ʃx/n = 74.6/9 = | 8.28888889 |
y̅ = Ʃy/n = 1490/9 = | 165.555556 |
SSxx = Ʃx² - (Ʃx)²/n = 618.4 - (74.6)²/9 = | 0.04888889 |
SSyy = Ʃy² - (Ʃy)²/n = 250106 - (1490)²/9 = | 3428.22222 |
SSxy = Ʃxy - (Ʃx)(Ʃy)/n = 12343.7 - (74.6)(1490)/9 = | -6.74444444 |
a) Appropriate test statistic : Correlation
b) Null and alternative hypothesis:
Ho: ρ = 0 ; Ha: ρ < 0
α = 0.01
df = n-2 = 7
Critical value, t_c = ABS(T.INV(0.01, 7)) = -2.9980
Test statistic :
t = r*√(n-2)/√(1-r²) = -0.521 *√(9 - 2)/√(1 - -0.521²) = -1.6148
Fail to reject H0
c) Coefficient of determination, r² = (SSxy)²/(SSxx*SSyy) = (-6.74444)²/(0.04889*3428.22222) = 0.2714
small effect
d) Sodium intake does not significantly predict blood pressure.