1. 3.37 g of NaH2PO4 in a total volume of 0.600 L 2. 23.7 g of...

1. 3.37 g of NaH2PO4 in a total volume of 0.600 L

2. 23.7 g of citric acid (C6H8O7) in a total volume of 153 mL

3. 137 mg of lidocaine hydrochloride (C14H23N2OCl) in a total volume of 5.50 mL

4. A solution contains 5.0 g of ethanol in enough water to give a total volume of 52.0 mL. Express the concentration of this solution in a percent concentration (w/v).

5. You need to make 10.0 mL of a 0.30 M solution of triethylamine. How many grams of triethylamine must you use?

Expert Solution

Solution 1-4

Solution 5

The steps are very easy.molarity is determined by moles of solute per litre . 1 mole is 101.1 g of triethylamine . So if you mix 101.1 g in 1000mL of 1L then this is 1 M. Here we need .3M in 10ml and get .303 gm.

Hope you understand...Thank you !!

queen_honey_blossom answered 2 years ago

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