Question

In: Civil Engineering

A concrete masonry unit has actual gross dimensions of 7-5/8” x 7-5/8” x 7-5/8”. The unit...

A concrete masonry unit has actual gross dimensions of 7-5/8” x 7-5/8” x 7-5/8”. The unit is tested in a compression machine with the following results:

Failure load = 98,000 lb

Net volume = 348.1 in³

Is the unit categorized as solid or hollow?
Calculate the gross area compressive strength.
Calculate the net area compressive strength.

please answer by typing, i will rate your answer.

thanks

Expert Solution

Solution:-

Given data:

Concrete masonry gross dimension = 7-5/8" × 7-5/8" × 7-5/8"

Failure load = 98,000 lb

Net volume = 348.1 in³

Gross area of the concrete masonry unit:

Gross area = B × L

= (7-5/8")(7-5/8")

= (7.625")(7.625")

= 58.140 in²

Net area of the concrete masonry unit:

Net area = Net volume / H

= 348.1 in³ / 7-5/8 in

= 348.1 in³ / 7.625 in

= 45.652 in²

A). If the Net cross-sectional area of the masonry unit is less than 75% of the Gross cross-sectional area, then the masonry units is Hollow masonry unit and if the Net cross-sectional area is greater than 75% of the Gross cross-sectional area, then the masonry is Solid masonry unit.

Gross area of the concrete masonry:

Gross area = 58.140 in² × (75/100)

= 43.605 in²

The Net cross-sectional area of the masonry unit is greater than 75% Gross cross-sectional area.

Therefore, the concrete masonry unit is a solid masonry unit.

B). Gross area compression strength of the concrete masonry:

Gross area compressive strength = Failure load / Gross area

= 98,000 lb / 58.140 in²

= 1685.586 lb/in²

C). Net area compressive strength of the concrete masonry:

Net area compressive strength = Failure load / Net area

= 98,000 lb / 45.652 in²

= 2146.674 lb/in²

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