Question
In: Statistics and Probability
Assigned Problem: On New Year's Eve, the probability of a person driving while intoxicated or having...
Assigned Problem:
On New Year's Eve, the probability of a person driving while intoxicated or having a driving accident is 0.38. If the probability of driving while intoxicated is 0.31 and the probability of having a driving accident is 0.11, find the probability of a person having a driving accident while intoxicated.
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Expert Solution
P(driving while intoxicated or having a driving accident) = 0.38
P(driving while intoxicated) = 0.31
P(having a driving accident) = 0.11
P(driving while intoxicated and having a driving accident) = P(driving while intoxicated) + P(having a driving accident) - P(driving while intoxicated or having a driving accident)
= 0.31 + 0.11 - 0.38
= 0.04
P(having a driving accident | while intoxicated) = P(driving while intoxicated and having a driving accident) / P(driving while intoxicated)
= 0.04 / 0.31
= 0.129
orchestra answered 2 years agoRelated Solutions
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