In: Operations Management
The So's Hobby Shop carries a line of radio-controlled model racing cars. Average daily demand for the model cars is 100 with a standard deviation of 30. Unit inventory holding cost is estimated at $0.90/year. The shop purchases the model cars from one supplier. It is estimated that the ordering cost is $100 per order. The delivery lead time is 10 working days. Mr. So decides to use a Reorder Point System to control the inventory of the model cars and wants to achieve a service level of 90%. Assume 300 working days per year.
a)
Daily Demand | µD | = | 100 | |
Standard Deviation of Daily Demand | σD | = | 30 | |
Working days per year | n | = | 300 | |
Annual Demand | D | = | n*µD | 30,000 |
Lead Time (Days) | L | = | 10 | |
Desired Service level | α | = | 90% | |
Z-value corresponding to Service Level | Zα | = | NORMSINV(α) | 1.28 |
Safety stock | ss | = | ZασD √L | 121 |
Reorder Point | R | = | µD*L + ss | 1,121 |
Annual Holding Cost per Unit | H | = | $0.90 | |
Ordering Cost per Order | S | = | $100 | |
Optimal Order Qty | Q* | = | √(2SD/H) | 2,582 |
Optimal reorder point, R = 1121
EOQ = 2582
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b)
Average inventory = EOQ/2 + Safety stock
= 2582/2 + 121
= 1412
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c)
New lead time, L = 3 days
Revised safety stock = 1.28*30*sqrt(3)
= 67
EOQ remains unchanged.
New average inventory = 2582/2+67
= 1358
Reduction in average inventory = 1412 - 1358
= 54
Savings = 54*0.9
= $ 48.6