In: Finance
XYZ Corp. will pay a $2 per share dividend in two months. Its stock price currently is $90 per share. A call option on XYZ has an exercise price of $85 and 3-month time to expiration. The risk-free interest rate is 0.6% per month, and the stock’s volatility (standard deviation) = 24% per month. Find the Black-Scholes value of the option. (Hint: Try defining one “period” as a month, rather than as a year, and think about the net-of-dividend value of each share.)
Dividend paid after 2 months = $2
Risk free rate = r = 0.006
Present Value of the dividend = D/(1+r)n = 2/(1+0.006)2 = 1.98
Net of Dividend Value of share = 90 - 1.98 = 88.02
S = Net Value of share = | 88.02 |
t = time until option expiration(years) = 3/12 = | 0.2500 |
K = Option Strike Price = | 85 |
r = risk free rate(annual) = 0.6*12/100 = | 0.072 |
s = standard deviation(annual) = 24% = | 0.24 |
N = cumulative standard normal distribution | |
d1 | = {ln (S/K) + (r +s^2/2)t}/s√t |
= {ln (88.02/85) + (0.072 + 0.24^2/2)*0.25}/0.24*√0.25 | |
0.500900 | |
d2 | = d1 - s√t |
= 0.5009 - 0.24√0.25 | |
0.3809 | |
Using z tables, | |
N(d1) = | 0.6918 |
N(d2) = | 0.6484 |
C = Call Premium = | =SN(d1) - N(d2)Ke^(-rt) |
= 88.02*0.6918 - 0.6484*85e^(-0.072*0.25) | |
6.7614 | |
N(-d1) = | 0.3082 |
N(-d2) = | 0.3516 |
P = Put Premium = | =N(-d2)Ke^(-rt) - SN(-d1) |
= 0.3516*85e^(-0.072*0.25) - 88.02*0.3082 | |
2.2251 |
Hence, Value of call option = $6.76