Question

The number of U.S. dial-up Internet households stood at 42.5 million at the beginning of

2004 and was projected to decline at the rate of 3.9 million households per year for the next 6

years.

a) Find a linear function f giving the projected U.S. dial up Internet households (in

millions) in year t, where t = 0 corresponds to the beginning of 2004.

b) What is the projected number of U.S. dial-up Internet households at the beginning

of 2010?

Answer 1

number of us dial-up Internet households at the beginning a of year 2004 = 42.5 millions Projected rate of decline (for next 6 years) = 3.9 millions household Hence, Sole 2004 = 4 @ fole 2004 = 42.5 millions 2005 = 42.5 - 3.9 = 38.6 millions 2006 = 38.6-3.9 = 34.7 millions 2007 = 34.7-3.9 = 2018 millions 2008 = 3018-319= 26.9 millions 2009 = 26.9- 319 23.0 millions 2010 = 23.0-319= 1911 millions To find a linear function to, and t=0 fore year 2004 On the basis of above results, we can have it year (No of household o 2004 | 42.5 millions Now, Equation I 2005 / 38.6 for a millions [2 Linear function 2006 34.7 millions 13 [2007 30.8 millions Y = mx + b 4 /2008 1 26.9 millin I can also be tamt tb Is 2009 23:0 millions To 2010 1 where, ma slope 19.1 millions There m=-3,9 = -3.9 t = ~3:9 (t) tb After Putting value for tool 38.6= ~319 (1) th 38.6 -3.9 + b + 3.9 +3.9 42.6 = b Hence, Linear function is f -39 (t) +4267 No. of households at the beggining of year 2010 = ~319 (6) + 42 62 [1911 millions) y written as one 1