In: Chemistry
Consider the following balanced equation for the combustion of butane, a fuel often used in lighters:
2C4H10(g)+13O2(g)→8CO2(g)+10H2O(g)2C4H10(g)+13O2(g)→8CO2(g)+10H2O(g)
Complete the following table, showing the appropriate masses of reactants and products. If the mass of a reactant is provided, fill in the mass of other reactants required to completely react with the given mass, as well as the mass of each product formed. If the mass of a product is provided, fill in the required masses of each reactant to make that amount of product, as well as the mass of the other product that is formed.
Mass C4H10C4H10 | Mass O2O2 | Mass CO2CO2 | Mass H2OH2O |
_____ | 2.11 gg | _____ | _____ |
5.52 gg | _____ | _____ | _____ |
_____ | _____ | 10.12 gg | _____ |
_____ | _____ | _____ | 8.04 gg |
222 mgmg | _____ | _____ | _____ |
_____ | _____ | 128 mgmg | _____ |
Here we are asked to find mass of reactants and products
We use conversion factors from balanced reaction
2C4H10(g)+13O2(g)→8CO2(g)+10H2O(g)
Mass of C4H10 =
=0.588 g C4H10
Similarly we can solve for products
Mass of CO2 =
Mass of H2O =
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In the next row we are given with Mass of C4H10 = 5.52 g
Mass of O2 required =
Mass of CO2 formed =
Mass of H2O formed =
Similarly we can solve remaining blanks