In: Physics
The emitting antenna of a 100-kW radio station radiates equally in all directions.
Part A
What is the magnitude Emax 600 m from the antenna?
Express your answer to two significant digits and include the appropriate units.
Emax =
Part B
What is the magnitude Bmax 600 m from the antenna?
Express your answer to two significant digits and include the appropriate units.
Bmax =
Part C
For the distance of 600 m from the antenna, calculate the maximum potential difference caused between the ends of a receiving antenna that is 1.0 m long, assuming the antenna is aligned perfectly with the electric field of the radio wave.
Express your answer to two significant digits and include the appropriate units
V =
Part D
What is the magnitude Emax 50 km from the antenna?
Express your answer with the appropriate units.
Emax =
Part E
What is the magnitude Bmax 50 km from the antenna?
Express your answer with the appropriate units.
Bmax =
Part F
For the distance of 50 km from the antenna, calculate the maximum potential difference caused between the ends of a receiving antenna that is 1.0 m long, assuming the antenna is aligned perfectly with the electric field of the radio wave.
Express your answer with the appropriate units.
V =
a)
P = power = 100 kW = 105 Watt
r = distance = 600 m
I = intensity
Intensity is given as
I = P/(4r2)
I = 105/(4 (3.14) (600)2)
I = 0.022 W/m2
amplitude of electric field is given as
Emax = sqrt(2I/(c))
Emax = sqrt(2(0.022)/((8.85 x 10-12) (3 x 108)))
Emax = 4.1 N/C
b)
amplitude of magnetic field is given as
Bmax = Emax /c
Bmax = 4.1/(3 x 108) = 1.4 x 10-8 T
c)
L = length of recieving antenna = 1 m
maximum potential difference is given as
Vmax = Emax L = 4.1 x 1 = 4.1 volts
d)
P = power = 100 kW = 105 Watt
r = distance = 50 km = 50,000 m
I = intensity
Intensity is given as
I = P/(4r2)
I = 105/(4 (3.14) (50000)2)
I = 3.2 x 10-6 W/m2
amplitude of electric field is given as
Emax = sqrt(2I/(c))
Emax = sqrt(2(3.2 x 10-6)/((8.85 x 10-12) (3 x 108)))
Emax = 0.049 N/C
e)
amplitude of magnetic field is given as
Bmax = Emax /c
Bmax = 0.049/(3 x 108) = 1.63 x 10-10 T
f)
maximum potential difference is given as
Vmax = Emax L = 0.049 x 1 = 0.049 volts