Question

Use the following information for questions 16 – 18:

A study is conducted to find a relationship between heavy alcohol use during the first trimester of pregnancy and miscarriage. 50 women who suffered miscarriage are enrolled along with 70 women who delivered full-term. Each participant’s use of alcohol during pregnancy is found via survey. The data are shown here.

	Miscarriage	Delivered Full-Term
Heavy Alcohol Use	33	19
No Heavy Alcohol Use	17	51

What is the incidence of miscarriage in this study?

a. 0.583

b. 0.635

c. 0.417

d. 0.271

What is the incidence of miscarriage in heavy alcohol users?

a) 0.660

b) 0.271

c) 0.250

d)0.635

What is the incidence of miscarriage in this study in non-heavy alcohol users?

a) 0.250

b) 0.583

c) 0.635

D) 0.271

Using Excel or a Z score table, find the probability of a Z score being less than 1.04

a. 0.1587

b. 0.0808

c. 0.9192

d. 0.8413

Using Excel or a Z score table, find the probability of a Z score being greater than 0.72.

a. 0.7611

b. 0.2358

c. 0.2676

d. 0.7939

SAT scores are normally distributed with a mean of 100 and a standard deviation of 15. If a person is picked at random, what is the probability that the person has an IQ greater than 88?

a. 0.7910

b. 0.2119

c. 0.7881

d. 0.1841

BMI is normally distributed with a mean of 22.5 kg/m² and a standard deviation of 4.1 kg/m². An obese person is defined as someone who has a BMI of greater than 30 kg/m². What is the probability of randomly finding a person who is obese?

a. 0.0336

b. 0.9664

c. 0.9732

d. 0.0418

Answer 1

Solution:-) The follwing information is given that is the total number of events is

a) We have to find the probability of miscarriage in this study. So let A denotes the number of miscarrige in this study which is

Hence,option(C) is correct.

b) We have to find the probability of  of miscarriage in heavy alcohol users. Let A denotes the event of miscarriage in heavy alcohol users.

hence, option(D) is correct.

c) We have to find the probability of  of miscarriage in non heavy alcohol users. Let A denotes the event of miscarriage in non heavy alcohol users.

hence, option(A) is correct.

d) The probability of a Z score being less than 1.04 that is

Using excel command =NORMDIST(1.04,0,1,TRUE)

Hence, option(D) is correct.

e) The probability of a Z score being greater than 0.72.

Using excel command =1-NORMDIST(0.72,0,1,TRUE)

Hence, option(B) is correct.

f) Given

The probability that the person has an IQ greater than 88.

  

Hence, option (C) is correct

g)

Given

The probability that the person has BMI is greater than 30

  

Hence, option (A) is correct

CHEERS!!