Question

In: Statistics and Probability

Recently, the number of children Americans have has dropped. The Gallup Poll organization wanted ... Recently,...

Recently, the number of children Americans have has dropped. The Gallup Poll organization wanted ... Recently, the number of children Americans have has dropped. The Gallup Poll organization wanted to know whether this was a change in attitude or possibly a result of the recession, so they asked Americans whether they have children, dont have children but wish to, or dont want children. Out of a random sample of 1200 American adults in 2013, 1140 said that they either have children or want/wish to.

(a) Suppose the margin of error in the confidence interval above were 0.02. What would that represent? The proportion of people in our sample who lied or misunderstood the question is 0.02. We actually called 1224 people; however, since 2% of them chose not to participate in our poll, we have an effective sample size of only 1200.

Our prediction is that the proportion of all Americans that have or want children is no more than 0.02 away from 0.95, the difference being due to randomness.

The difference between the actual proportion of Americans that have or want children and our sample proportion because of people lying or misunderstanding the question is 0.02.

The typical distance between the proportion of all Americans that have or want children and a sample proportion from a sample of size 1200 is 0.0

(b) If the margin of error were 0.02, the 95% confidence interval would be (0.93, 0.97). How would we interpret this interval in context?

I am 95% confident that the proportion of all Americans who said they have or want children is between 0.93 and 0.97.

In repeated sampling, 95% of the time, we would create an interval that captures the sample proportion of Americans who said they have or want children. This is one such interval.

There is a 95% chance that the proportion of Americans in the sample who said they have or want children is between 0.93 and 0.97.

There is a 95% chance that the proportion of all Americans who said they have or want children is between 0.93 and 0.97.

I am 95% confident that the proportion of Americans in the sample who said they have or want children is between 0.93 and 0.97.

(c) In 1990, 94% of all Americans either had children or wanted children. Has the proportion of all Americans who have or wish they had children changed since then? (Use the confidence interval (0.93, 0.97) for simplicity.) Why or why not?

Yes, because proportions are not the same from one sample to the next.

Yes, because 1140/1200 = 0.95 is not equal to 0.94. No, because 0.94 is in the confidence interval above.

Yes, because 0.94 is in the confidence interval above.

No, because 0.94 and 0.95 are not very far apart.

Solutions

Expert Solution

(a) Suppose the margin of error in the confidence interval above were 0.02. What would that represent?

The margin of error represents the difference between the sample proportion and lower limit of the confidence interval or the difference between upper limit of the confidence interval and the sample proportion.

Sample proportion = 1140/1200 = 0.95

Thus, the correct answer is,

Our prediction is that the proportion of all Americans that have or want children is no more than 0.02 away from 0.95, the difference being due to randomness.

(b) If the margin of error were 0.02, the 95% confidence interval would be (0.93, 0.97). How would we interpret this interval in context?

Interpretation of 95% confidence interval is - We're 95% confident that the interval (0.93, 0.97) captured the true proportion of all Americans that have or want children.

Thus, the correct answer is,

I am 95% confident that the proportion of all Americans who said they have or want children is between 0.93 and 0.97.

(c) In 1990, 94% of all Americans either had children or wanted children. Has the proportion of all Americans who have or wish they had children changed since then? (Use the confidence interval (0.93, 0.97) for simplicity.) Why or why not?

Since the value 94% lies in the confidence interval, there is no significant evidence that the proportion of all Americans who have or wish they had children changed since then.

Thus, the correct answer is,

No, because 0.94 is in the confidence interval above.


Related Solutions

1) In a recent poll, the Gallup organization found that 45% of adult Americans believe that...
1) In a recent poll, the Gallup organization found that 45% of adult Americans believe that the overall state of moral values in the United States is poor. Suppose a survey of a random sample of 25 adult Americans is conducted in which they are asked to disclose their feelings on the overall state of moral values in the United States. Answer the questions below, showing work. Bare answers are not acceptable. (Showing work means writing the calculator command you...
1) In a recent poll, the Gallup organization found that 45% of adult Americans believe that...
1) In a recent poll, the Gallup organization found that 45% of adult Americans believe that the overall state of moral values in the United States is poor. Suppose a survey of a random sample of 25 adult Americans is conducted in which they are asked to disclose their feelings on the overall state of moral values in the United States. Answer the questions below, showing work. Bare answers are not acceptable. (Showing work means writing the calculator command you...
A Gallup poll found that 493 of 1050 adult Americans believe it is the responsibility of...
A Gallup poll found that 493 of 1050 adult Americans believe it is the responsibility of the federal government to make sure all Americans have healthcare coverage. Construct and interpret a 90% confidence interval for the proportion of adult americans who believe it is the federal governments responsibility to make sure all americans have coverage? What does this interval suggest?
A Gallup Poll showed that 44% of Americans are satisfied with the way things are going...
A Gallup Poll showed that 44% of Americans are satisfied with the way things are going in the United States. Suppose a sample of 25 Americans are selected. Based on this information, generate a cumulative binomial probability. Binomial n 25 p 0.44 xi P(X<=xi) 0 0.0000 1 0.0000 2 0.0001 3 0.0007 4 0.0031 5 0.0112 6 0.0323 7 0.0773 8 0.1569 9 0.2750 10 0.4235 11 0.5826 12 0.7285 13 0.8431 14 0.9203 15 0.9647 16 0.9866 17 0.9956...
A Gallup Poll showed that 44% of Americans are satisfied with the way things are going...
A Gallup Poll showed that 44% of Americans are satisfied with the way things are going in the United States. Suppose a sample of 25 Americans are selected. Find the probability that no less than 7 Americans are satisfied with the way things are going. Find the probability that exactly 15 Americans are not satisfied with the way things are going. Find the probability that the number of Americans who are satisfied with the way things are going differs by...
A poll done for an organization found that 13% of Americans have seen or sensed the...
A poll done for an organization found that 13% of Americans have seen or sensed the presence of an angel. A contingent doubts that the percent is really that high. It conducts its own survey. Out of 78 Americans surveyed, only two had seen or sensed the presence of an angel. As a result of the contingent's survey, would you agree with the organization's poll? Conduct a hypothesis test at the 5% level. Note: If you are using a Student's...
According to a Gallup Poll, 18% of Americans surveyed said that they had gained “a lot”...
According to a Gallup Poll, 18% of Americans surveyed said that they had gained “a lot” of weight in the past five years. Assume that this result is true for the current population of Americans. A random sample of 14 Americans is selected. a.Find the probability that in a random sample of 14 Americans, the number who will say they have gained “a lot” of weight in the past five years is at most 2. Draw a distribution b. Find...
2. According to a Gallup poll conducted in 2008, 78.3% of Americans felt satisfied with the...
2. According to a Gallup poll conducted in 2008, 78.3% of Americans felt satisfied with the way things were going in their personal lives. A researcher wonders of the percentage satisfied is lower today. To find out, the researcher surveys a random sample of 1,173 Americans, and finds that 895 feel satisfied with the way things are going in their personal lives. The researcher wishes to test the null hypothesis at a significance level of 0.05. (a) Conduct a large...
A Gallup poll to survey the top concerns of Americans was conducted. Suppose that 387 women...
A Gallup poll to survey the top concerns of Americans was conducted. Suppose that 387 women and 359 men were independently and randomly selected, and that 242 women and 202 men chose the state of the economy as their biggest concern. Can we conclude that the proportion of women (p1), choosing the state of the economy as their biggest concern, exceeds the proportion of men (p2)?  Use a significance level of α=0.01 for the test. Step 1: Choose the correct alternative...
4. A 2012 Gallup poll surveyed Americans about their employment status and whether or not they...
4. A 2012 Gallup poll surveyed Americans about their employment status and whether or not they have diabetes. The survey results indicated that 717 of the 47,774 employed (full or part time) and 146 of the 5,855 unemployed 18-29 year olds have diabetes. (a) If you suspect that that having diabetes and being unemployed might be related somehow, then what is the null and alternative hypothesis? (b) What is the pooled proportion? (c) What is the standard error? (SE) (d)...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT