In: Statistics and Probability
Red | Orange | Yellow | Green | Purple | Total |
1046. | 1066 | 977 | 1029 | 969 | 5087 |
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(a)
Since, ten Skittles are selected with replacement, the probability of yellow Skittles in a selection = 977 / 5087 = 0.192
The number of yellow Skittles in 10 selected Skittles follow binomial probability distribution with n = 10, p = 0.192
For the binomial probability distribution, below conditions are met.
Thus, all the requirements of the binomial probability distribution are met.
(b)
Probability that exactly 4 of the 10 Skittles are yellow = P(X = 4)
= 10C4 * 0.1924 * (1 - 0.192)10-4
= 210 * 0.1924 * 0.8086
= 0.0794
(c)
Probability that at most 2 of the 10 Skittles are yellow = P(X 2)
= P(X = 0) + P(X = 1) + P(X = 2)
= 10C0 * 0.1920 * (1 - 0.192)10-0 + 10C1 * 0.1921 * (1 - 0.192)10-1 + 10C2 * 0.1922 * (1 - 0.192)10-2
= 0.1186 + 0.2818 + 0.3014
= 0.7018
Expected value = np = 10 * 0.192 = 1.92
standard deviation for the number of yellow skittles = = = 1.245536