Write a function (in Javascript) called longestMorseCodeWords which takes in an array of strings. The output...

Write a function (in Javascript) called longestMorseCodeWords which takes in an array of strings. The output of longestMorseCodeWords should be an array of the strings that were passed in, but ordered by the length of their Morse Code equivalent in descending order. If the length of Morse Code is equal, order the words alphabetically.For convenience, the full table for the 26 letters of the English alphabet is given below:

[".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]

let words = ["gin", "zen", "gig", "msg"]

longestMorseCodeWords(words)

The Morse Code equivalent of the words above is ["--...-.", "--...-.", "--...--.", "--...--."]. Ordering by length, it's [7, 7, 8, 8]. When we alphabetize based off of length in descending order, the output should be # ['gig', 'msg', 'gin', 'zen'].

Solutions

Expert Solution

JavaScript Code


function longestMorseCodeWords(words) {
    // Inititalized Morse Code in an array
    let morsecode = [".-", "-...", "-.-.", "-..", ".", "..-.", "--.", "....", "..",
        ".---", "-.-", ".-..", "--", "-.", "---", ".--.", "--.-", ".-.", "...", "-",
        "..-", "...-", ".--", "-..-", "-.--", "--.."];
    let alphabets = "abcdefghijklmnopqrstuvwxyz";
    let morseCodeArray = []; // Has Morse Code equivalent of the words
    let morseCodeString = "";
    for (let i = 0; i < words.length; i++) {
        for (let j = 0; j < words[i].length; j++) {
            morseCodeString += morsecode[alphabets.indexOf(words[i][j])];
        }
        morseCodeArray[i] = morseCodeString;
        morseCodeString = "";
    }
    let morseCodeArrayLength = []; // Has Length of the morse code
    for (let k = 0; k < morseCodeArray.length; k++) {
        morseCodeArrayLength[k] = morseCodeArray[k].length;
    }
    let finalArray = []; // Has the final output;
    let tempArray = [];
    for (let m = Math.max.apply(null, morseCodeArrayLength); m >= Math.min.apply(null, morseCodeArrayLength); m--) {
        while (morseCodeArrayLength.indexOf(m) != -1) { // Runs till there is not element of the same length
            tempArray.push(words[morseCodeArrayLength.indexOf(m)]);
            words.splice(morseCodeArrayLength.indexOf(m), 1);
            morseCodeArrayLength.splice(morseCodeArrayLength.indexOf(m), 1);
        }
        tempArray.sort(); // Sorts Alphabetically
        for (let l = 0; l < tempArray.length; l++) {
            finalArray.push(tempArray[l]);
        }
        tempArray = [];
    }
    return finalArray; // Returns the final sorted array of words in the descending order of length
}
let words = ["zen","gig", "gin", "msg"]; // Input Words array
console.log(longestMorseCodeWords(words));

OUTPUT:

venereology answered 7 months ago

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