In: Statistics and Probability
For a simple random sample of adults, IQ scores are normally distributed with a mean of 100 and a standard deviation of 15. A simple random sample of 13 statistics professors yields a standard deviation of s = 7.2. Assume that IQ scores of statistics professors are normally distributed and use a 0.05 significance level to test the claim that = 15. Use the Traditional Method
Null and alternative hypotheses
Ho : = 15
Ha : 15
Level of significance a = 0.05
Test statistic
2 = ( n-1)*s2/ 2
= 12* 7.22/152
2 = 2.76
2critical value for a = 0.05 , d.f = n -1 = 12
Using chi square table
2critical = 20.025, 12
2critical = 4.40 , 23.34
Decision rule : if chi square < 4.40 or > 23.34 we reject the null hypothesis otherwise fail to reject the null hypothesis
Here 2.76 < 4.40
Decision : we reject the null hypothesis
Conclusion : There is no sufficient evidence to support the claim that = 15