In: Math
A study examined parental influence on the decisions of teenagers from a certain large region to smoke. A randomly selected group of students, from the region, who had never smoked were questioned about their parents' attitudes toward smoking. These students were questioned again two years later to see if they had started smoking. The researchers found that, among the
263
students who indicated that their parents disapproved of kids smoking,
53
had become established smokers. Among the
43
students who initially said their parents were lenient about smoking,
18
became smokers. Do these data provide strong evidence that parental attitude influences teenagers' decisions about smoking? Complete parts a through i below.
a) What kind of design did the researchers use?
A prospective observational study
Your answer is correct.
An experimental study
A retrospective observational study
b) Write the appropriate hypotheses. Let
p1
be the proportion of students whose parents disapproved of smoking who became smokers. Let
p2
be the proportion of students whose parents were lenient about smoking who became smokers.
Choose the correct answer below.
A.
H0:
p1minus
p2equals
0
HA:
p1minus
p2greater than
0
B.
H0:
p1minus
p2equals
0
HA:
p1minus
p2not equals
0
Your answer is correct.
C.
H0:
p1minus
p2not equals
0
HA:
p1minus
p2equals
0
D.
H0:
p1minus
p2greater than
0
HA:
p1minus
p2equals
0
c) Are the assumptions and conditions necessary for inference satisfied?
A.
No, because the Independent Groups Assumption is not satisfied.
B.
Yes, all of the assumptions and conditions are satisfied.
Your answer is correct.
C.
No, because the Success/Failure Condition is not satisfied.
D.
No, because the 10% Condition is not satisfied.
E.
No, because the Randomization Condition is not satisfied.
d) Test the hypothesis and state the conclusion.
Determine the test statistic.
zequals
negative 3.13
(Round to two decimal places as needed.)
Find the P-value.
Pequals
. 002
(Round to three decimal places as needed.)
State the conclusion. Use a significance level of
alpha
equals0.10
.
Choose the correct answer below.
A.
Do not reject
the null hypothesis. There
is
sufficient evidence that parental attitude influences teenagers' decisions about smoking.
B.
Do not reject
the null hypothesis. There
is not
sufficient evidence that parental attitude influences teenagers' decisions about smoking.
C.
Reject
the null hypothesis. There
is not
sufficient evidence that parental attitude influences teenagers' decisions about smoking.
D.
Reject
the null hypothesis. There
is
sufficient evidence that parental attitude influences teenagers' decisions about smoking.
Your answer is correct.
e) Explain in this context what your P-value, P, means. Choose the correct answer below.
A.
If the observed difference is the true difference, then there is about a
(100 times
P)%
chance that there is no difference in the proportions.
B.
If there is no difference in the proportions, there is about a
(100 times
P)%
chance of seeing the observed difference or larger by natural sampling variation.Your answer is correct.
C.
There is about a
(100 times
P)%
chance that there is no difference in the proportions.
D.
There is about a
(100 times
P)%
chance that there is a difference in the proportions.
f) If that conclusion is actually wrong, which type of error was committed?
A.
A Type
II
error was committed because the null hypothesis is
false
,
but was
not
rejected.
B.
A Type
Upper I
error was committed because the null hypothesis is
true
,
but was
mistakenly
rejected.
Your answer is correct.
g) Create a 90%CI for the difference of two proportions,p 1 minus p 2
. I am having trouble with G.)
The researchers found that, among the
263: students who indicated that their parents disapproved of kids smoking,
53: had become established smokers.
Among the 43 students who initially said their parents were lenient about smoking,
18 became smokers.
p1: be the proportion of students whose parents disapproved of smoking who became smokers.
p2: be the proportion of students whose parents were lenient about smoking who became smokers.
n1 : Number of students who indicated that their parents disapproved of kids smoking=263
n2 : Number students who initially said their parents were lenient about smoking = 43
: Sample proportion of students whose parents disapproved of smoking who became smokers =53/263 = 0.2015
: Sample proportion of students whose parents were lenient about smoking who became smokers = =18/43 = 0.4186
Formula for confidence interval for difference of two population proportions : p1-p2
: Sample Size of Sample 1 | 263 |
: Sample Size of Sample 2 | 43 |
: Sample Propotion of Sample 1 | 0.2015 |
: Sample Propotion of Sample 2 | 0.4186 |
Confidence Level | 90% |
(= 100-90/100=10/100 ) = 0.1 | 0.1 |
/2 (=0.1/2=0.05) | 0.05 |
1.6449 |
90% Confidence Interval for Difference in two Population proportions p1 - p2
90% Confidence Interval for Difference in two Population proportions p1 - p2 : =(-0.3474,-0.0868)