1 mol of Ar is expanded from 2L to 8L and from 25C to 100C instantaneously....

1 mol of Ar is expanded from 2L to 8L and from 25C to 100C instantaneously. Find the change in entropy of this process. THE HINT GIVEN IN CLASS WAS: P = 1mol* 0.082 atmL/molK* 298K / 2L = 12.218 atm =12.05 bar)

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Expert Solution

pressure(P) = nRT/V

= 1*0.0821*298/2

= 12.233 atm

work done(w) = - p*DV

= -12.233*(8-2)

= -73.298 l.atm

( 1 l.atm = 101.3 joule)

= -78.298*101.3

= -7931.6 joule

q = -w = 7931.6 j

change in temperature(DT) = 100-25 = 75

change in entropy(DS) = q/DT = 7931.6/75 = 105.75 j/c

queen_honey_blossom answered 2 years ago

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