If pH of 1 liter of a 1.0mM carbonate buffer is 7.0, what is actual number...

If pH of 1 liter of a 1.0mM carbonate buffer is 7.0, what is actual number of moles of H2CO3 and HCO3? (pk=6.37)

Expert Solution

pH ofacidic buffer = pka + log(salt/acid)

7 = 6.37 + log(HCO3^-/H2CO3)

HCO3^-/H2CO3 = 4.266

salt = HCO3^-

Acid = H2CO3

HCO3^-/H2CO3 = 4.266

TOtal no of mol of buffer = 1*1 = 1*10^-3 mol

No of mol of acid(H2CO3) = x

TOtal no of mol of buffer = H2CO3 + HCO3^-

= x+4.266x = 10^-3

x = 0.00019 mol

No of mol of acid(H2CO3) = x = 0.00019 mol

No of mol of salt(HCO3^-) = (10^-3)-x

= (10^-3) - (0.00019)

= 0.00081 mol

queen_honey_blossom answered 2 years ago

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