1) Find y as a function of t if 9y′′+24y′+32y=0,
y(0)=5,y′(0)=8. y(t)=
2) Find y as a function of x if y′′′+16y′=0,
y(0)=−5, y′(0)=−32, y′′(0)=−32. y(x)=
3) Find y as a function of t if 9y′′−12y′+40y=0,
y(1)=5,y′(1)=9. y=
Find y as a function of x:
y'''-12y''+27y'=80e^x
y(0)=29
y'(0)=11
y''(0)=21
I found the roots to be r=0,3,9 and c1=224/9 c2=13/3 c3=-2/9
not sure what is wrong with the answer I'm entering.
A) Solve the initial value problem:
8x−4y√(x^2+1) * dy/dx=0
y(0)=−8
y(x)=
B) Find the function y=y(x) (for x>0 ) which
satisfies the separable differential equation
dy/dx=(10+16x)/xy^2 ; x>0
with the initial condition y(1)=2
y=
C) Find the solution to the differential equation
dy/dt=0.2(y−150)
if y=30 when t=0
y=