Question

1. Write the isotope needed, by identifying A, Z, and X, to balance the following nuclear fission reaction: 23592U+10n→14054Xe+AZX+4 10

2. Complete each of the following nuclear equations:

Part A 10n+?→13253I+0−1e Express your answer as an isotope. Part B 42He+12250Sn→?+11H Express your answer as an isotope. Part C ?→3517Cl+0−1e Express your answer as an isotope. Part D 42He+24195Am→?+210n Express your answer as an isotope 3. As part of her nuclear stress test, Simone starts to walk on the treadmill. When she reaches the maximum level, Paul injects a radioactive dye with 201Tl with an activity of 66 MBq . The radiation emitted from areas of her heart is detected by a scanner and produces images of her heart muscle. After Simone rests for 3 h, Paul injects more dye with 201Tl and she is placed under the scanner again. A second set of images of her heart muscle at rest is taken. The radioactive dye passes through the kidneys as it is filtered out of the body and eliminated after the medical testing is complete. Part A Radiation from 201Tl to Simone's kidneys can be 24 mGy . What is this amount of radiation in rad? Express the radiation to two significant figures and include the appropriate units.

Answer 1

1.

235U92+1n0→140Xe54 + 92X38 + 4 1n0

atomic mass = 235 +1 = 140 +A +4(1) =

A= 236 - 144 = 92

Atomic number, z = 92 = 54 + z

z = 92-54= 38

Atom number = 38 = Sr

²³⁵U₉₂ + ¹n₀ → ⁴⁰Xe₅₄ + ⁹²Sr₃₈ + 4 ¹n₀

2.

PartA)

¹₀n + ? → ¹³²₅₃I + ⁰₋₁e

Atomic number = z = 53 -1 = 52

atomic number, 52 = Te

Mass number =

1 + A = 132

A = 132- 1 = 131

¹₀n + ¹³¹₅₂Te → ¹³²₅₃I + ⁰₋₁e

Part B)

⁴₂He +¹²²₅₀Sn → ? + ¹₁H

Atomic number = 50 + 2 = z +1

52 = z + 1

z = 51

element with atomic number 51 is = Sb

Atomic mass = 4 + 122 = A+1

A+1= 126

A = 125

⁴₂He +¹²²₅₀Sn → ¹²⁵₅₁Sb + ¹₁H

Part C)

? → ³⁵₁₇Cl + ⁰₋₁e

Atomic mass = A = 35

Atomc number = z = 17-1 = 16

Element with atomic number,16 = S

³⁵₁₆S → ³⁵₁₇Cl + ⁰₋₁e

Part D)

⁴₂He + ²⁴¹₉₅Am → ? + 2¹₀n

Atomic number = 2+95 = z + 0

z = 97

elmemnt with atomic number 97 = Bk

Atomic mass = 4 + 241 = A + 2

A = 245 - 2 = 243

Atomic mass = 243

⁴₂He + ²⁴¹₉₅Am → ²⁴³₉₇Bk + 2¹₀n

3.

Part A)

mGy to rad

= 2.4 rad