In: Math
The pages per book in a library are normally distributed with an unknown population mean and standard deviation. A random sample of 41 books is taken and results in a sample mean of 341 pages and sample standard deviation of 22 pages. Find the EBM, margin of error, for a 95% confidence interval estimate for the population mean using the Student's t-distribution.
Solution: Given that n = 41, mean = 341, sd = 22, 95% Confidence
interval
df = n-1 = 41 - 1 = 40, t(0.05,40) = 2.021
Margin of error = t*s/sqrt(n) = 2.021*22/sqrt(41) = 6.9438
95% confidence interval estimate for the population mean : x +/-
t*s/sqrt(n)
= 341 +/- 2.021*22/sqrt(41)
= (334.0562 , 347.9438)