Question

In: Computer Science

# Do not delete this cell. You have to run this cell to test your code...

# Do not delete this cell. You have to run this cell to test your code in the test cases.
score = dict()

# This function will search the given text in order to find a given word

def is_word_there(text, word):
  
    """
        What it takes?
            a text to be searched
            a word to be searched within a text
          
        what it does?
            searches if a word occurs in a text
          
        What it returns?
            returns 1 if word is in the text.
            returns -1 if word is not in the text
    """
  
    # your code goes in here
  
    return
   

Test Case for Question 1. Do not delete or alter the cell below

score = dict()

text = """ Python is an amazing programming language.
            Python is also one of the primary languages in the data analysis field"""

word = "amazing"

try:
    if is_word_there(text, word) ==1:
        score['question 1'] = 'pass'
    else:
        score['question 1'] = 'fail'
except:
    score['question 1'] = 'fail'
  
is_word_there(text, word)

Solutions

Expert Solution


# Do not delete this cell. You have to run this cell to test your code in the test cases.

# This function will search the given text in order to find a given word
def is_word_there(text, word):
  """
    What it takes?
      a text to be searched
      a word to be searched within a text
    
    what it does?
      searches if a word occurs in a text
      
    What it returns?
      returns 1 if word is in the text.
      returns -1 if word is not in the text
  """
  # your code goes in here
  text_to_array = text.split()
  if word in text_to_array:
    return 1
  else:
    return -1
   

score = dict()

text = """ Python is an amazing programming language. Python is also one of the primary languages in the data analysis field"""
word = "amazing"

try:
  if is_word_there(text, word) == 1:
    score['question 1'] = 'pass'
  else:
    score['question 1'] = 'fail'
except:
  score['question 1'] = 'fail'
  
is_word_there(text, word)

# test command
print(score)


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