In: Physics
A = 3, B = 9, C = 18. A (1.25+A) kg bowling ball is hung on a (2.50+B) m long rope. It is then pulled back until the rope makes an angle of (12.0+C) degrees with the vertical and released. Find the speed of the ball is at the lowest point. Give your answer in m/s and with 3 significant figures.
mass of the ball, m = (1.25 + A) Kg = (1.25 + 3) Kg = 4.25 Kg
length of the rope, L = (2.50 + B) m = (2.50 + 9) m = 11.5 m
angle made by the rope, θ = (12.0 + C) degrees = (12.0 + 18) degrees = 30.0 degrees
speed at the highest point is 0 m/s2. So the kinetic energy at the highest point is, K.E.high = 0 Joule
Let the speed at the lowest point is u. So the kinetic energy at the lowest point is, K.E.low = ( m u2 / 2 ) Joule
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