In: Math
A farmer decides to enclose a rectangular garden, using the side of a barn as one side of the rectangle. What is the maximum area that the farmer can enclose with 60 ft of fence? What should the dimensions of the garden be to give this area?
The maximum area that the farmer can enclose with 60ft is _____ sq feet
The larger dimension of the garden to give this area is ______ and the smaller dimension is _____
The perimeter of a rectangle is
Since one side is formed from the side of the barn, this means that
we can take out one length (or width, it doesn't matter) to
get
Plug in the given perimeter 60 (since he only has 60 ft of
fencing)
The area of any rectangle is
Plug in
From now on, let's think of
as
where y is the area and x is the width.
Now the equation is in the form of a quadratic which has a vertex
that corresponds with the maximum area. So if we find the
y-coordinate of the vertex, we can find the max area.
In order to find find the vertex, we first need to find the axis of
symmetry (ie the x-coordinate of the vertex)
To find the axis of symmetry, use this formula:
From the equation
we can see that a=-2 and b=60
Plug in b=60 and a=-2
So the axis of symmetry is
So the x-coordinate of the vertex is
. Lets plug this into the equation to find the y-coordinate of the
vertex.
Lets evaluate
Plug in
So the vertex is (15,450)
This shows us that the max area is then 450 square feet.
So with a width of 15 ft the fence will have a maximum area of 450
square feet
Now plug in
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Answer:
The maximum area that the farmer can enclose with 60ft is _450_ sq feet
The larger dimension of the garden to give this area is 30_ and the smaller dimension is 15