Calculate the pH of a solution made by mixing 49.5 mL of 0.335 M
NaA (Ka for HA = 1.0 x 10^-9) with 30.6 mL of 0.120 M HCl.
The answer given was 9.55. But I am stuck on how to get there
after the ICE table. Can someone include a step by step.
50 mL of 2.0 M NaOH is added to a 1.0L buffer solution that is
0.20M in HF and 0.20M in KF. The ka for HF is 3.5 x 10^-4.
1. Write the reaction or the buffer only including states and
excluding spectator ions.
2. Write the neutralization reaction that occurs after the
addition of LiOH including states and excluding spectator ions.
3. Calculate the amount of moles remaining and the final
concentration for each component of the solution after...
A 200 mL solution of .100 M solution of Ammonia, NH3, is slowly
mixed with .100 M HCl. Determine the pH after addition of: 0 ml of
HCl, 50 mL of HCl, 100 mL of HCl, 200 mL of HCl, and 250 mL of
HCl.
A 200 mL solution of .100 M solution of Ammonia, NH3, is slowly
mixed with .100 M HCl. Determine the pH after addition of: 0 ml of
HCl, 50 mL of HCl, 100 mL of HCl, 200 mL of HCl, and 250 mL of
HCl.
A
solution of 100 mL of .200M sodium chromate is mixed with a
solution of 200 mL of 0.150M strontium nitrate. What is the is the
limiting reagent or reacting? How many grams of percipitate forms?
What is the concentration of spectator ions in the final mixture?
What is the concentration of the excess ion?
If 100.mL of 0.035 M HCl solution is added to 220.mL of a buffer
solution which is 0.20M in NH3 and 0.18M in NH4Cl, what will be the
pH of the new solution? The Kb of NH3 is 1.8x10^-5.
Please explain how the answer was obtained. Thank you!
A solution contains 0.306 M HA (Ka = 6.43 ⋅ 10 − 5 ) and 0.683 M
NaA. What is the pH of this solution? What is the pH of this
solution after 0.233 mol of HCl are added to 1.00 L of this
solution? What is the pH of this solution after 0.466 mol of HCl
are added to 1.00 L of this solution?
Determine the pH of the solution of 100 mL of 0.150 M benzoic
acid, HC7H5O2 (Ka=6.3x10-5 ). To this 25.0 mL of 0.400 M KOH is
added, calculate the pH of the resulting solution. In a second step
an additional 12.5ml of 0.400M KOH is added, calculate the pH of
the resulting solution.