In: Math
Let t 0 be a specific value of t. Use the table of critical values of t below to find t 0 dash values such that following statements are true. a. Upper P left parenthesis t greater than or equals t 0 right parenthesisequals.025, where dfequals11 b. Upper P left parenthesis t greater than or equals t 0 right parenthesisequals.01, where dfequals18 c. Upper P left parenthesis t less than or equals t 0 right parenthesisequals.005, where dfequals7 d. Upper P left parenthesis t less than or equals t 0 right parenthesisequals.05, where dfequals14 LOADING... Click the icon to view the table of critical values of t.
Solution:
We have to use t critical value table to find t values for following parts.
Part a)
P( t > t0) =0.025
df = 11
Since it says P( t > t0) =0.025, it means this is one tail area
thus look in t table for One tail area = 0.025 and df = 11 and find t value.
t value = 2.201
that is: t0= 2.201
Part b)
P( t >t0) = 0.01
df = 18
look in t table for One tail area = 0.01 and df = 18 and find t value.
thus t0= 2.552
Part c)
P( t <t0) = 0.005
df = 7
Since it says P( t <t0) = 0.005, this is one tailed but left tailed, so t value is negative.
We use same table and same way but we give - sign for the value obtained.
look in t table for One tail area = 0.005 and df = 7 and find t value.
t0= -3.499
Part d)
P( t < t0) = 0.05
df = 14
look in t table for One tail area = 0.05 and df = 14 and find t value.
t0= -1.761