In: Statistics and Probability
Group |
Sample Mean |
Std. Err. |
DF |
L. Limit |
U. Limit |
---|---|---|---|---|---|
Infant |
62.556325 |
1.5340462 |
331 |
59.538616 |
65.574035 |
WHO region |
n |
Mean |
Variance |
Std. dev. |
Std. err. |
Median |
Range |
Min |
Max |
Q1 |
Q3 |
Africa |
336 |
104.16012 |
2217.9031 |
47.094618 |
2.5692221 |
92.3 |
296.4 |
30 |
326.4 |
70.65 |
128.7 |
Test if the African average infant mortality rate is different from 62.56 using the population standard deviation 27.91 and normal distribution for α=0.05.
we have population standard deviation ,
These values are provided in the data table given above.
We have to use the z distribution because the population standard deviation is known.
we have to test whether the Africa average infant mortality rate is different from 62.56 or not
So, null hypothesis will be
and alternate hypothesis will be
This is a two tailed hypothesis testing
Calculation for the test statistic
z statistic =
setting the given values, we get
z statistic =
Using the z distribution table for the z value of 1.49 (two tailed hypothesis), we get
p value = 0.1362
We failed to reject the null hypothesis because the p value is greater than 0.05 level of significance, which makes the p value insignificcant at 0.05 level.
Thus, we can conclude that we have insufficient evidence to support the claim that the African average infant mortality rate is different from 62.56.