In: Math
Let C be the curve of intersection of the parabolic cylinder x2 = 2y, and the surface 3z = xy. Find the exact length of C from the origin to the point
(5, 25/2,125/6)
Step 1)
Hence we can say that,
Hence,
Step 2)
we have,
Hence we can say that,
(x,y,z) = (0,0,0) corresponds to t = 0
(x,y,z) = (5,25/2,125/6) corresponds to t = 5
Hence we can say that t ranges form t = 0 to t = 5
we know that length of parametric curve r(t) is given by,
we have,
we have a = 0 and b = 5 hence,
Hence we can say that length of C from origin to the point (5,25/2,125/6) is L = 155/6