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In 2011, when the Gallup organization polled investors, 34% rated gold the best long-term investment. In...

In 2011, when the Gallup organization polled investors, 34% rated gold the best long-term investment. In April of 2013 Gallup surveyed a random sample of U.S. adults. Respondents were asked to select the best long-term investment from a list of possibilities. Only 241 of the 1005 respondents chose gold as the best long-term investment. By contrast, only 91 chose bonds.

  1. Compute the standard error for each sample proportion. Compute and describe a 95% confidence interval in the context of the question.
  2. Do you think opinions about the value of gold as a long-term investment have really changed from the old 34% favorability rate, or do you think this is just sample variability? Explain.
  3. Suppose we want to increase the margin of error to 3%, what is the necessary sample size?
  4. Based on the sample size obtained in part c, suppose 120 respondents chose gold as the best long-term investment. Compute the standard error for choosing gold as the best long-term investment. Compute and describe a 95% confidence interval in the context of the question.
  5. Based on the results of part d, do you think opinions about the value of gold as a long-term investment have really changed from the old 34% favorability rate, or do you think this is just sample variability? Explain.

(Please show calculations especially if formatted via excel)

Solutions

Expert Solution

Answer:

Formulas:

Given

population poroportion p0 =

0.34

number of trails n=

1005

Number of respondents for gold x=

241

sample proportion p=

=C4/C3

a)

Standard error

=SQRT(C5*(1-C5)/C3)

Confidence level =

0.95

level of significance alpha =

=1-C9

confidence interval =

Lower limit

=C5-ABS(NORM.INV(C10/2,0,1))*C8

Upper Limit

=C5+ABS(NORM.INV(C10/2,0,1))*C8

Explanation:-

we are 95% confident that the proportion investors in gold is in between(0.213 , 0.266)

b)

Yes the opnions have changed significantly because the population proportion does not exist in the 95% CI

c)

Margin of error E =

0.03

required Sample size n=

=ROUND(((NORM.INV(C10/2,0,1)/C18))^2*C2*(1-C2),0)

d)

number of trails n=

=C20

Number of respondents for gold x=

120

sample proportion p=

=C23/C22

Standard error

=SQRT(C24*(1-C24)/C22)

Confidence level =

0.95

level of significance alpha =

=1-C28

confidence interval =

Lower limit

=C24-ABS(NORM.INV(C29/2,0,1))*C27

Upper Limit

=C24+ABS(NORM.INV(C29/2,0,1))*C27

Explanation:-

we are 95% confident that the proportion investors in gold is in between(0.104 , 0.146)

e

Yes the opnions have changed significantly because the population proportion does not exist in the 95% CI


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