Question

Equation: TiCl4+H2O=TiO2+HCI

Question: You need to make 5505g of TiO2.

A.) Determine how many grams of TiCl4 are needed to make the desired amount of product

B.) How many grams of water are needed to make desired amount of product?

C.) Determine the theoretical yield of HCI in grams.

Answer 1

The bakanced reaction is

TiCl4 + 2H2O ------> TiO2 + 4HCl

A) Number of moles = mass/Molar mass

Mass of TiO2 required = 5505g

Molar mass of TiO2 = 47.867g/mol

Number of moles of TiO2 required = 5505g/79.867g/mol = 68.927mol

From the balanced equation we know that 1mole of TiO2 is obtained from 1mole of TiCl4

So,

68.927moles of TiO2 is obtained from 68.927 moles of TiCl4

Molar mass of TiCl4 = 189.679g/mol

mass of TiCl4 required = 68.927mol × 189.679mol = 13074g

Part B

From the balanced equation we know that 2moles of H2O is reaquired to produce 1mole of TiO2

so,

To prepare 68.927mol of TiO2, 2×68.927g/mol= 137.854mol of H2O are required

molar mass of H2O = 18.016g/mol

mass of H2O required = 18.016g/mol × 137.854mol = 2484g

Part C

From the balanced equation we know that 4moles of HCl is obtained for 1mole of TiO2 formation

Therefore,

No of moles of HCl formed = 4× 68.927mol = 275.71mol

molar mass of HCl = 36.461g/mol

mass of HCl formed = 36.461g/mol × 275.71mol = 10053g