Question

In: Statistics and Probability

The age in weeks at which babies first crawl is assumed to be normally distributed. A...

The age in weeks at which babies first crawl is assumed to be normally distributed. A survey of 15 mothers conducted by Essential Baby resulted in a sample standard deviation of s = 12 . A) In order to construct a 90% confidence interval, we must determine the values α/2 and (1 − α/2) . Determine the two values. B) Construct a 90% confidence interval for the population standard deviation of the age (in weeks) at which babies first crawl.

Solutions

Expert Solution

Solution :

Given that,

c = 0.90

s = 12

n = 15

A)

At 90% confidence level the is ,

= 1 - 90% = 1 - 0.90 = 0.10

/ 2 = 0.10 / 2 = 0.05

/2,df = 0.05,14 = 23.68

and

1- /2,df = 0.95,14 = 6.57

2L = 2/2,df = 23.68

2R = 21 - /2,df = 6.57

B)

The 90% confidence interval for is,

s (n-1) / /2,df < < s (n-1) / 1- /2,df

12 ( 15 - 1 ) / 23.68 < < 12 ( 15 - 1 ) / 6.57

9.23 < < 17.52

( 9.23 , 17.52 )


Related Solutions

The following data represent the age (in weeks) at which babies first crawl based on a...
The following data represent the age (in weeks) at which babies first crawl based on a survey of 12 mothers conducted by Essential Baby. Crawling ages (in weeks) are known to be normally distributed. 52 30 44 35 39 26 47 37 56 25 39 28 Please include the letter each part below as you answer the following questions. a) What is the point estimate for the population mean number of weeks babies first crawl? b) Shall we use a...
The following data represent the age (in weeks) at which babies first crawl based on a...
The following data represent the age (in weeks) at which babies first crawl based on a survey of 12 mothers conducted by Essential Baby. Crawling ages (in weeks) are known to be normally distributed. 52 30 44 35 39 26 47 37 56 25 39 28 Please include the letter each part below as you answer the following questions. a) What is the point estimate for the population mean number of weeks babies first crawl? b) Shall we use a...
The data shown to the right represent the age​ (in weeks) at which babies first​ crawl,...
The data shown to the right represent the age​ (in weeks) at which babies first​ crawl, based on a survey of 12 mothers. Complete parts​ (a) through​ (c) below. 52 30 44 35 47 37 56 26 54 44 35 28 Click here to view the table of critical t-values. LOADING... Click here to view page 1 of the standard normal distribution table. LOADING... Click here to view page 2 of the standard normal distribution table. LOADING... ​(a) Draw a...
The following data represent the age​ (in weeks) at which babies first crawl based on a...
The following data represent the age​ (in weeks) at which babies first crawl based on a survey of 12 mothers. The data are normally distributed and sequals9.190 weeks. Construct and interpret a 95​% confidence interval for the population standard deviation of the age​ (in weeks) at which babies first crawl. 49 31 43 35 37 26 46 36 55 26 38 29 A. If repeated samples are​ taken, 95​% of them will have the sample standard deviation between ___ and...
The following data represent the age in weeks at which babies first crawl based on a...
The following data represent the age in weeks at which babies first crawl based on a survey of 12 mothers conducted by Essential Baby. 52 30 44 35 39 26 47 37 56 26 39 28 a. Draw a normal probability plot (use Statcrunch) and boxplot to determine if it is reasonable to conclude the data come from a population that is normally distributed. Copy/paste the graphs into your solution along with an explanation of why or why not. b....
1, The data shown to the right represent the age​ (in weeks) at which babies first​...
1, The data shown to the right represent the age​ (in weeks) at which babies first​ crawl, based on a survey of 12 mothers. Complete parts​ (a) through​ (c) below. 52 30 44 35 47 37 56 26 30 35 26 30 ​(c) Construct and interpret a 95​% confidence interval for the mean age at which a baby first crawls. Select the correct choice and fill in the answer boxes to complete your choice. ​(Round to one decimal place as​...
The weight of newborn babies are normally distributed with a mean of 7.62 pounds and a...
The weight of newborn babies are normally distributed with a mean of 7.62 pounds and a standard deviation of 0.61 pounds. If the weight of 22 newborn are randomly selected, what's the probability that their mean weight is more than 7.23 pounds? Round to 4-decimal places
The weights for newborn babies is approximately normally distributed with a mean of 5lbs and a...
The weights for newborn babies is approximately normally distributed with a mean of 5lbs and a standard deviation of 1.5lbs. Consider a group of 1,000 newborn babies: How many would you expect to weigh between 4-7lbs? How many would you expect to weigh less than 6lbs? How many would you expect to weigh more than 5lbs? How many would you expect to weigh between 5-10lbs?
The birthweight of newborn babies is Normally distributed with a mean of 3.39 kg and a...
The birthweight of newborn babies is Normally distributed with a mean of 3.39 kg and a standard deviation of 0.55 kg. (a) Find the probability that a baby chosen at random will have a birthweight of over 3.5 kg. (b) Find the probability that an SRS of 16 babies will have an average birthweight of over 3.5 kg. (c) Find the probability that an SRS of 100 babies will have an average birthweight of over 3.5 kg. (d) What range...
The distribution of heights of basketball players is assumed to be normally distributed with a mean...
The distribution of heights of basketball players is assumed to be normally distributed with a mean of 75 inches and standard deviation of 5 inches. Approximately what percent of basketball players have heights more than 90 inches? The distribution of heights of basketball players is assumed to be normally distributed with a mean of 75 inches and standard deviation of 5 inches. Approximately what percent of basketball players have heights more than 80 inches? The distribution of heights of basketball...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT