a 15.04 gram sample of chromium is heated in the presence of excess iodine. a metal...

a 15.04 gram sample of chromium is heated in the presence of excess iodine. a metal iodide is formed with a mass of 125.2g. determine the empirical formula of the metal iodide

Expert Solution

mass of Cr = 15.04 g

molar mass of Cr = 51.96 g / mol

moles of Cr = mass / molar mass

= 15.04 / 51.96

= 0.290

mass of Iodine = 125.2 - 15.04

= 110.14 g

moles of I = mass / molar mass

= 110.4 / 126.9

=0.868

moles ratio = Cr : I

= 0.290 : 0.868

= 1 : 3

empirical formula = CrI₃ (chromium (III) iodide)

queen_honey_blossom answered 2 years ago

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