1.) A 25.3 mL sample of 0.329 M triethylamine, (C2H5)3N, is titrated with 0.344 M nitric...

1.) A 25.3 mL sample of 0.329 M triethylamine, (C₂H₅)₃N, is titrated with 0.344 M nitric acid.

The pH before the addition of any nitric acid =

2.) A 20.8 mL sample of 0.275 M triethylamine, (C₂H₅)₃N, is titrated with 0.304 M hydrochloric acid.

At the equivalence point, the pH =

Expert Solution

queen_honey_blossom answered 2 years ago

A 20.8 mL sample of 0.304 M triethylamine, (C2H5)3N, is titrated with 0.341 M hydroiodic acid....

A 20.8 mL sample of 0.304 M triethylamine, (C2H5)3N, is titrated with 0.341 M hydroiodic acid. (1) Before the addition of any hydroiodic acid, the pH is (2) After adding 7.53 mL of hydroiodic acid, the pH is (3) At the titration midpoint, the pH is (4) At the equivalence point, the pH is (5) After adding 26.5 mL of hydroiodic acid, the pH is Please show step by step instructions, many thanks!

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