Question

Do you want to own your own candy store? Wow! With some interest in running your own business and a decent credit rating, you can probably get a bank loan on startup costs for franchises such as Candy Express, The Fudge Company, Karmel Corn, and Rocky Mountain Chocolate Factory. Startup costs (in thousands of dollars) for a random sample of candy stores are given below. Assume that the population of x values has an approximately normal distribution.

91

179

130

91

75

94

116

100

85

(a) Use a calculator with mean and sample standard deviation keys to find the sample mean startup cost x and sample standard deviation s. (Round your answers to one decimal place.)

x =	thousand dollars
s =	thousand dollars

(b) Find a 90% confidence interval for the population average startup costs μ for candy store franchises. (Round your answers to one decimal place.)

lower limit	thousand dollars
upper limit	thousand dollars

Answer 1

TRADITIONAL METHOD
given that,
sample mean, x =106.11
standard deviation, s =30.0768
sample size, n =9
I.
standard error = sd/ sqrt(n)
where,
sd = standard deviation
n = sample size
standard error = ( 30.0768/ sqrt ( 9) )
= 10
II.
margin of error = t α/2 * (standard error)
where,
ta/2 = t-table value
level of significance, α = 0.1
from standard normal table, two tailed value of |t α/2| with n-1 = 8 d.f is 1.86
margin of error = 1.86 * 10
= 18.6
III.
CI = x ± margin of error
confidence interval = [ 106.11 ± 18.6 ]
= [ 87.5 , 124.8 ]
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DIRECT METHOD
given that,
sample mean, x =106.11
standard deviation, s =30.0768
sample size, n =9
level of significance, α = 0.1
from standard normal table, two tailed value of |t α/2| with n-1 = 8 d.f is 1.86
we use CI = x ± t a/2 * (sd/ Sqrt(n))
where,
x = mean
sd = standard deviation
a = 1 - (confidence level/100)
ta/2 = t-table value
CI = confidence interval
confidence interval = [ 106.11 ± t a/2 ( 30.0768/ Sqrt ( 9) ]
= [ 106.11-(1.86 * 10) , 106.11+(1.86 * 10) ]
= [ 87.5 , 124.8 ]
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interpretations:
1) we are 90% sure that the interval [ 87.5 , 124.8 ] contains the true population mean
2) If a large number of samples are collected, and a confidence interval is created
for each sample, 90% of these intervals will contains the true population mean
Answer:
a.
sample mean, x =106.1
standard deviation, s =30.1
b.
90% confidence interval for the population average startup costs μ for candy store franchises.
90% sure that the interval [ 87.5 , 124.8 ]