Question
In: Statistics and Probability
Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week....
Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week. A sample of 85 weekly reports showed a sample mean of 17.5 customer contacts per week. The sample standard deviation was 5.3. Provide 90% and 95% confidence intervals for the population mean number of weekly customer contacts for the sales personnel.
A. 90% Confidence interval, to 2 decimals:
(___,____)
B. 95% Confidence interval, to 2 decimals:
(__,___)
Solutions
Expert Solution
Solution :
Given that,
A.
t
/2,df = 1.663
Margin of error = E = t/2,df
* (s /
= 1.663 * (5.3 /
Margin of error = E = 0.96
The 90% confidence interval estimate of the population mean is,
- E < 
<
+ E
17.5 - 0.96 <
< 17.5 + 0.96
16.54 <
< 18.46
90% Confidence interval is (16.54 , 18.46)
B.
t
/2,df = 1.989
Margin of error = E = t/2,df
* (s /
= 1.989 * (5.3 /
Margin of error = E = 1.14
The 95% confidence interval estimate of the population mean is,
- E <
<
+ E
17.5 - 1.14 <
< 17.5 + 1.14
16.36 <
< 18.61
95% Confidence interval is (16.36 , 18.61)
orchestra answered 2 years agoRelated Solutions
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Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week....
Sales personnel for Skillings Distributors submit weekly reports
listing the customer contacts made during the week. A sample of 85
weekly reports showed a sample mean of 19.5 customer contacts per
week. The sample standard deviation was 5.2. Provide 90% and 95%
confidence intervals for the population mean number of weekly
customer contacts for the sales personnel.
90% Confidence interval, to 2 decimals:
( , )
95% Confidence interval, to 2 decimals:
( , )
Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week....
Sales personnel for Skillings Distributors submit weekly reports
listing the customer contacts made during the week. A sample of 67
weekly reports showed a sample mean of 19.5 customer contacts per
week. The sample standard deviation was 5.2.
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of weekly customer contacts for the sales personnel. (Round your
answers to two decimal places.)
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week. The sample standard deviation was 5.5. Provide 90% and 95%
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Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week....
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weekly reports showed a sample mean of 16.5 customer contacts per
week. The sample standard deviation was 5.2.
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of weekly customer contacts for the sales personnel.
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Skillings Distributors submit weekly reports listing the customer
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standard deviation was 5.6. Provide 90% and 95% confidence
intervals for the population mean number of weekly customer
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interval, to 2 decimals:
( , )
95% Confidence
interval, to 2 decimals:
( , )
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