In: Statistics and Probability
For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.
A random sample of 5,320 permanent dwellings on an entire reservation showed that 1,662 were traditional hogans.
(a)
Let p be the proportion of all permanent dwellings on the entire reservation that are traditional hogans. Find a point estimate for p. (Round your answer to four decimal places.)
(b)
Find a 99% confidence interval for p. (Round your answer to three decimal places.)
lower limit
upper limit
Solution :
Given that,
n = 5320
x = 1662
Point estimate = sample proportion = = x / n = 1662/5320=0.3124
1 - = 1-0.3124= 0.6876
at 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 = 2.576 ( Using z table )
Margin of error = E = Z / 2 * (((( * (1 - )) / n)
= 2.576* (((0.3124*0.6876) /5320 )
E = 0.016
A 99% confidence interval for population proportion p is ,
- E < p < + E
0.3124 - 0.016 < p < 0.3124+0.016
lower limit 0.296
upper limit 0.328