In: Statistics and Probability
For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.
A random sample of 5,320 permanent dwellings on an entire reservation showed that 1,662 were traditional hogans.
(a)
Let p be the proportion of all permanent dwellings on the entire reservation that are traditional hogans. Find a point estimate for p. (Round your answer to four decimal places.)
(b)
Find a 99% confidence interval for p. (Round your answer to three decimal places.)
lower limit
upper limit
Solution :
Given that,
n = 5320
x = 1662
Point estimate = sample proportion =
= x / n = 1662/5320=0.3124
1 -
= 1-0.3124= 0.6876
at 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 =
0.01
/ 2 = 0.01 / 2 = 0.005
Z/2
= Z0.005 = 2.576 ( Using z table )
Margin of error = E = Z
/ 2 * (
(((
* (1 -
)) / n)
= 2.576* (((0.3124*0.6876)
/5320 )
E = 0.016
A 99% confidence interval for population proportion p is ,
- E < p <
+ E
0.3124 - 0.016 < p < 0.3124+0.016
lower limit 0.296
upper limit 0.328