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25.00 mL of MALIC ACID (H2C4H4O5) solution reacts completely with exactly 16.78 mL of 0.09974 M...

25.00 mL of MALIC ACID (H2C4H4O5) solution reacts completely with exactly 16.78 mL of 0.09974 M ALUMINUM HYDROXIDE solution. Write the balanced chemical reaction and calculate the molarity of the malic acid solution. Do NOT use M1 x V1 = M2 x V2.

Solutions

Expert Solution

2Al(OH)3(aq) + 3H2C4H4O5 ---------> Al2(C4H4O5)3 + 6H2O

2 moles               3 moles

H2C4H4O5                                                         Al(OH)3

M1 =                                                  M2 = 0.09974M   

V1   = 25ml                                                       V2   = 16.78ml

n1 = 3                                                               n2 = 2

                  M1V1/n1     =      M2V2/n2

                      M1           =    M2V2n1/V1n2

                                      = 0.09974*16.78*3/25*2    = 0.1M

the molarity of the malic acid solution   = 0.1M


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