In: Chemistry
25.00 mL of MALIC ACID (H2C4H4O5) solution reacts completely with exactly 16.78 mL of 0.09974 M ALUMINUM HYDROXIDE solution. Write the balanced chemical reaction and calculate the molarity of the malic acid solution. Do NOT use M1 x V1 = M2 x V2.
2Al(OH)3(aq) + 3H2C4H4O5 ---------> Al2(C4H4O5)3 + 6H2O
2 moles 3 moles
H2C4H4O5 Al(OH)3
M1 = M2 = 0.09974M
V1 = 25ml V2 = 16.78ml
n1 = 3 n2 = 2
M1V1/n1 = M2V2/n2
M1 = M2V2n1/V1n2
= 0.09974*16.78*3/25*2 = 0.1M
the molarity of the malic acid solution = 0.1M