Question
In: Chemistry
25.00 mL of MALIC ACID (H2C4H4O5) solution reacts completely with exactly 16.78 mL of 0.09974 M...
25.00 mL of MALIC ACID (H2C4H4O5) solution reacts completely with exactly 16.78 mL of 0.09974 M ALUMINUM HYDROXIDE solution. Write the balanced chemical reaction and calculate the molarity of the malic acid solution. Do NOT use M1 x V1 = M2 x V2.
Solutions
Expert Solution
2Al(OH)3(aq) + 3H2C4H4O5 ---------> Al2(C4H4O5)3 + 6H2O
2 moles 3 moles
H2C4H4O5 Al(OH)3
M1 = M2 = 0.09974M
V1 = 25ml V2 = 16.78ml
n1 = 3 n2 = 2
M1V1/n1 = M2V2/n2
M1 = M2V2n1/V1n2
= 0.09974*16.78*3/25*2 = 0.1M
the molarity of the malic acid solution = 0.1M
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