(a) Place a charge of -4.10 µC at point P and find themagnitude and direction...

EXAMPLE 15.5 Electric Field Due to Two Point Charges

GOAL Use the superposition principle to calculate the electric field due to two point charges

PROBLEM Charge q₁ = 7.00 μc is at the origin, and charge q₂ = -5.00 μc is on the x-axis, 0.300 m from the origin.

(a) Find the magnitude and direction of the electric field at point P, which has coordinates (0, 0.400) m. (b) Find the force on a charge of 2.00 x 10^-8 C placed at P.

STRATEGY Follow the problem-solving strategy, finding the electric field at point P due to each individual charge in terms of x- and y-components, then adding the components of each type to get the x- and y-components of the resultant electric field at P. The magnitude of the force in part (b) can be found by simply multiplying the magnitude of the electric field by the charge

(a) Place a charge of -4.10 µC at point P and find the magnitude and direction of the electric field at the location ofq₂ due to q₁ = 7.40 µC and the charge at P.

magnitude	_______ N/C
direction	_______ ° counterclockwise from the +x-axis

(b) Find the magnitude and direction of the force on q₂.

magnitude	_______ N
direction	_______ ° counterclockwise from the +x-axis

Solutions

Expert Solution

genius_generous answered 2 years ago

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