Question

In: Statistics and Probability

The mean number of pets per household is 3.45 with standard deviation 2.0. A sample of...

The mean number of pets per household is 3.45 with standard deviation 2.0. A sample of 48 households is drawn. Find the 44th percentile of the sample mean. A) 4.28 B) 4.11 C) 3.41 D) 2.65

Expert Solution

Given that,

mean = = 3.45

standard deviation = = 2

n = 48

= 3.45

= / n = 2/48=0.29

Using standard normal table,

P(Z < z) = 44%

= P(Z <-0.15 ) = 0.44

z =-0.15 Using standard normal table,

Using z-score formula

= z * +

= -0.15*0.29+3.45

= 3.41

orchestra answered 2 years ago

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