Calculate the pH of a solution that is 1.5 x 10^-8 M NaOH. This is a...

Calculate the pH of a solution that is 1.5 x 10^-8 M NaOH. This is a very dilute solution

Expert Solution

NaOH is strog base .For bases [OH^-] ion conc between 10^-1 to 10^-7 M

1.5*10^-8 M NaOH is very diluted solution.

Total conc of OH^- = conc of OH^- from NaOH + conc of OH^- from H2O

= 1.5*10^-8 + 10^-7

= 0.15*10^-7 + 10^-7

= (0.15+ 1) *10^-7

= 1.15*10^-7 M

POH = -log[OH^-]

= -log1.15*10^-7

= 6.9393

PH = 14-POH

= 14-6.9393 = 7.0607

queen_honey_blossom answered 2 years ago

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