In: Math
Tomato weights and Fertilizer: Carl the farmer has three fields of tomatoes, on one he used no fertilizer, in another he used organic fertilizer, and the third he used a chemical fertilizer. He wants to see if there is a difference in the mean weights of tomatoes from the different fields. The sample data is given below. The second table gives the results from an ANOVA test. Carl claims there is a difference in the mean weight for all tomatoes between the different fertilizing methods.
Tomato-Weight in Grams
x | |||||||||||
No Fertilizer | 123 | 119 | 95 | 97 | 94 | 120 | 114 | 118 | 129 | 128 | 113.7 |
Organic Fertilizer | 112 | 127 | 138 | 133 | 140 | 114 | 126 | 134 | 123 | 144 | 129.1 |
Chemical Fertilizer | 115 | 141 | 143 | 134 | 129 | 134 | 135 | 129 | 113 | 148 | 132.1 |
ANOVA Results
F | P-value |
6.921 | 0.0037 |
The Test: Complete the steps in testing the claim that there is a difference in the mean weight for all tomatoes between the different fertilizing methods.(a) What is the null hypothesis for this test?
H0: At least one of the population means is different from the others. H0: μ1 ≠ μ2 ≠ μ3. H0: μ1 = μ2 = μ3. H0: μ3 > μ2 > μ1.
(b) What is the alternate hypothesis for this test?
H1: μ1 ≠ μ2 ≠ μ3. H1: μ1 = μ2 = μ3. H1: μ3 > μ2 > μ1. H1: At least one of the population means is different from the others.
(c) What is the conclusion regarding the null hypothesis at the
0.05 significance level?
reject H0 fail to reject H0
(d) Choose the appropriate concluding statement.
We have proven that all of the mean weights are the same. There is sufficient evidence to conclude that the mean weights are different. There is not enough evidence to conclude that the mean weights are different.
(e) Does your conclusion change at the 0.01 significance level?
Yes No
Tomato weights and Fertilizer: Carl the farmer has three fields of tomatoes, on one he used no fertilizer, in another he used organic fertilizer, and the third he used a chemical fertilizer. He wants to see if there is a difference in the mean weights of tomatoes from the different fields. The sample data is given below. The second table gives the results from an ANOVA test. Carl claims there is a difference in the mean weight for all tomatoes between the different fertilizing methods.
Tomato-Weight in Grams
x |
|||||||||||
No Fertilizer |
123 |
119 |
95 |
97 |
94 |
120 |
114 |
118 |
129 |
128 |
113.7 |
Organic Fertilizer |
112 |
127 |
138 |
133 |
140 |
114 |
126 |
134 |
123 |
144 |
129.1 |
Chemical Fertilizer |
115 |
141 |
143 |
134 |
129 |
134 |
135 |
129 |
113 |
148 |
132.1 |
ANOVA Results
F |
P-value |
6.921 |
0.0037 |
The Test: Complete the steps in testing the claim that there is a difference in the mean weight for all tomatoes between the different fertilizing methods.
(a) What is the null hypothesis for this test?
. H0: μ1 = μ2 = μ3.
(b) What is the alternate hypothesis for this test?
H1: At least one of the population means is different from the others.
(c) What is the conclusion regarding the null hypothesis at the
0.05 significance level?
reject H0
( obtained p value 0.0037 is less than 0.05 level of significance)
(d) Choose the appropriate concluding statement.
There is sufficient evidence to conclude that the mean weights are different
(e) Does your conclusion change at the 0.01 significance level?
Yes
( obtained p value 0.0037 is less than 0.01 level of significance)
Excel used
One factor ANOVA |
|||||
Mean |
n |
Std. Dev |
|||
113.7 |
10 |
13.45 |
No Fertilizer |
||
129.1 |
10 |
10.70 |
Organic Fertilizer |
||
132.1 |
10 |
11.27 |
Chemical Fertilizer |
||
125.0 |
30 |
14.08 |
Total |
||
ANOVA table |
|||||
Source |
SS |
df |
MS |
F |
p-value |
Treatment |
1,949.07 |
2 |
974.533 |
6.921 |
.0037 |
Error |
3,801.90 |
27 |
140.811 |
||
Total |
5,750.97 |
29 |