1. What is the effect of slit width variation in Fluorescenece
Spectrum?
2. Why is the...
1. What is the effect of slit width variation in Fluorescenece
Spectrum?
2. Why is the fluoresence measured 90 degree from the exiciting
light source?
3. Why must the quinine solutions be acidified?
Solutions
Expert Solution
In Fluorescence spectroscopy, we can measure
the concentration of a sample based on their property of
fluorescence.
Molecules have various enery levels and each of these
electronic energy leveles are associated with a number of
vibrational energy levels.
A light source ( usually UV light) of a apecific wavelength is
passed through a sample. The sample absorbs a photon and an electro
from the ground state enery level gets excited to one of the
vibrational energy levels in the excited states. Due to number of
collisions, the electron drops down to the lowest vibrational state
of the excited state. Eventually, the electron drops down to the
vibrational states of the ground state.
In this process it emits a photon. This gives rise to both
absorption and emission spectra.
1)
Basically, slit width is the rectangular
spaces through which light enters and exits a monochromator in a
spectrometer.
It helps in effeciently separating close wavelengths of a light
source.
Slit width will alter the fluoresence of a sample. When we
increase the slit
width, the intensity of fluorescence
increases as more exciting light sources passes through the
sample. But, this decreases the resolution of
wavelength. The monochromator will not effectively separate
so many wavelengths from the broad light beam.
When we decrease the
slit width, the opposite happens. The fluorescence intensity
decreases but the targeted wavelength can be
obtained easily by the monochromator.
2)
Monochromators are used in the
instrument.
The monochromator helps to transmit light of the targeted wavelength to the
sample, among the different wavalengths that come from the exciting
light source.
As mentioned in the question, fluorescence is measured 90 degrees
from the light source. This position is preferred over
placing the sample in line of the excitation source.
This is to avoid the interference of the unwanted
wavelengths with the detected fluorescence light.
The monochromator will transmit this unwanted wavelength in the
form of stray
light. So that this light does not interfere in the
measurement of fluoresence, sample is placed at 90 degrees to the
light source.
3)
Acidified quinine solution is an ideal standard for
fluorescence spectroscopy
This solution has optimum quantum yield. Quantum
yield is the ration of photons absorbed to the photons emitted by a
sample.
Also, optimum
absorbance occurs for quinine in acidified solution. And,
quinine decomposes in
water. Hence, it is necessary to acidify the solution.
Width of Peak (cm): 1.6 Width of Slit for Single Peak: 2.3
The width of the center peak (w) can be calculated using the
equation w = 2λL/ a
where a is the width of the slit. Use this equation to determine
the width of the slit that caused the diffraction pattern. Show
your work.
I am confused as to what I am finding since I do not have L. I
have going backwards λL = 1.84. If someone could...
With the use of diagrams, explain why the slit width of a prism
wavelength selector must be varied to provide constant effective
bandwidths (specific wavelengths) but a constant slit width instead
can be used to provide constant bandwidth with a grating
monochromator?
calculate the frequency in hertz, the wave number in cm-1
Calculate the frequency in hertz, the wave number in cm!, the
energy in joules, and the energy associated with the 317 nm
wavelength energy source achieved from a...
A 10-slit aperture, with slit spacing five times the slit width
of 10^-4 cm, is used to produce a Fraunhofer diffraction pattern
with light of wavelength
435.8 nm. Determine the light intensity of the principal
interference maxima of orders 1, 2, 3, 4 and 5 relative to the
central fringe of zeroth order.
1) What is the relation of Spread Spectrum with
multiplexing?2) What feature of spread spectrum with what multiplexing
technique, to be for military uses?
Why does multiple slit experiment have unequal fringes?
What is the effect of adding more slits?
What is the effect of increasing the width of the slit in a
double slit experiment?
You have been asked to measure the width of a slit in a piece of paper. You mount the paper 80 centimeters from a screen and illuminate it from behind
with laser light of wavelength 633 nanometers (in air). You mark two of the intensity minima
as shown in the figure, and measure the distance between them to be 17.9 millimeters.What is the width a of the slit?
A single-slit diffraction pattern is formed on a distant screen.
If the width of the single slit through which light passes is
reduced, what happens to the width of the central bright fringe?
Assume the angles involved remain small.
The
central bright fringe becomes
wider.
The
central bright fringe remains the same
size.
The
effect cannot be determined unless the distance between the slit
and the screen is
known.
The
central bright fringe becomes narrower.
A beam of electrons is incident on a single slit whose
width could be varied with as high precision as we like. Assuming
that we would like to resolve 1% difference in momentum, please
estimate the slit width that would be necessary to resolve the
interference pattern of the electrons if their kinetic energy is
(a) 0.02 MeV, (b) 0.8 MeV and 120 MeV?
Hint: one does not need to do
a detailed interference pattern analysis here, just use your...