Question

In: Biology

34. Consider two single-gene traits in pea plants: Green pods (G) are dominant to Yellow pods...

34. Consider two single-gene traits in pea plants: Green pods (G) are dominant to Yellow pods (g).Tall plants (T) are dominant to Dwarf plants (t).Two plants which are heterozygous for both traits are crossed. GgTt x GgTt What fraction of the offspring would be Tall plants with Green pods?

1/4

3/16

1/16

9/16

31. A man with AB type blood and a woman with O type blood have children together. What blood types would be seen in their offspring and in what ratio?

1 A : 1 B

9 AB : 3 A : 3 B : 1 O

1 AB : 1 O

3 AB : 1 O


30. For the trait pod shape, pea plants are either inflated (Q), or constricted (q). Inflated is the dominant form. In the P generation, A homozygous dominant pea plant is crossed with a plant possessing the constricted phenotype.If two individuals from the F1 generation are bred together, What percentage of the F2 generation would you expect to have the constricted phenotype?

50%

100%

75%

25%

Solutions

Expert Solution

34. The correct option is : 9/16

Green pod - G

Yellow pod - g

G is dominant over g

Tall plant - T

Dwarf plant - t

T is dominant over t

F2 generation = GgTt x GgTt

i) Gg x Gg

G g
G GG (green) Gg (green)
g Gg (green) gg (yellow)

Therefore, green pods = 3/4

ii) Tt x Tt

T t
T TT (tall) Tt (tall)
t Tt (tall) tt (dwarf)

Therefore, tall plants = 3/4

Therefore, total fraction of offsprings of tall plant with green pods are = (3/4) * (3/4) = 9/16

31. The correct option is 1A : 1B

The alleles of AB blood type: IA IB

The alleles of O blood type : IO IO

IA IB
IO IA IO IB IO
IO IA IO IB IO

Therefore, the blood type of offsprings = IA IO = Blood type A and IB IO = Blood type B

The ratio is A : B = IA IO : IB IO = 1 : 1

30. The correct option is : 25%

Inflated pea plant = Q

Constricted pea plant = q

Q is dominant over q

P generation = QQ x qq

F1 generation = Qq

F2 generation = Qq x Qq

Q q
Q QQ (inflated) Qq (inflated)
q Qq (inflated) qq (constricted)

Therefore the constricted phenotype = 1/4 = 0.25 = 25%


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