In: Biology
34. Consider two single-gene traits in pea plants: Green pods (G) are dominant to Yellow pods (g).Tall plants (T) are dominant to Dwarf plants (t).Two plants which are heterozygous for both traits are crossed. GgTt x GgTt What fraction of the offspring would be Tall plants with Green pods?
1/4
3/16
1/16
9/16
31. A man with AB type blood and a woman with O type blood have children together. What blood types would be seen in their offspring and in what ratio?
1 A : 1 B
9 AB : 3 A : 3 B : 1 O
1 AB : 1 O
3 AB : 1 O
30. For the trait pod shape, pea plants are either inflated (Q), or
constricted (q). Inflated is the dominant form. In the P
generation, A homozygous dominant pea plant is crossed with a plant
possessing the constricted phenotype.If two individuals from the F1
generation are bred together, What percentage of the F2 generation
would you expect to have the constricted phenotype?
50%
100%
75%
25%
34. The correct option is : 9/16
Green pod - G
Yellow pod - g
G is dominant over g
Tall plant - T
Dwarf plant - t
T is dominant over t
F2 generation = GgTt x GgTt
i) Gg x Gg
G | g | |
G | GG (green) | Gg (green) |
g | Gg (green) | gg (yellow) |
Therefore, green pods = 3/4
ii) Tt x Tt
T | t | |
T | TT (tall) | Tt (tall) |
t | Tt (tall) | tt (dwarf) |
Therefore, tall plants = 3/4
Therefore, total fraction of offsprings of tall plant with green pods are = (3/4) * (3/4) = 9/16
31. The correct option is 1A : 1B
The alleles of AB blood type: IA IB
The alleles of O blood type : IO IO
IA | IB | |
IO | IA IO | IB IO |
IO | IA IO | IB IO |
Therefore, the blood type of offsprings = IA IO = Blood type A and IB IO = Blood type B
The ratio is A : B = IA IO : IB IO = 1 : 1
30. The correct option is : 25%
Inflated pea plant = Q
Constricted pea plant = q
Q is dominant over q
P generation = QQ x qq
F1 generation = Qq
F2 generation = Qq x Qq
Q | q | |
Q | QQ (inflated) | Qq (inflated) |
q | Qq (inflated) | qq (constricted) |
Therefore the constricted phenotype = 1/4 = 0.25 = 25%