Question
In: Statistics and Probability
1. The average time to run a race is 14 minutes. You wish to see if...
1. The average time to run a race is 14 minutes. You wish to see if a new training regimen will lower the time to run the race. After doing the training regimen you run the race 35 times and the average time to run the race now is 13.32 minutes with a standard deviation of 1.4 minutes. a) At the .05 level did the training regimen lower the time (note: p value from computer is p = .003) b) Based on the answer for a) did the training regimen lower the time? (yes or no) Answer: c) What is the only type of error that could have occurred Answer: D) Interpret the p-value: Answer: E) How do you explain the .68 minutes lowering of the time
I need part e answered
Solutions
orchestra answered 2 years agoRelated Solutions
(14) 1. The average time to run a race is 14 minutes. You wish to see...
(14) 1. The average time to run a race is 14 minutes. You wish
to see if a new training regimen will lower the time to run the
race. After doing the training regimen you run the race 35 times
and the average time to run the race now is 13.32 minutes with a
standard deviation of 1.4 minutes.
a) At the .05 level did the training regimen lower the time
(note: p value from computer is p = .003)...
1. The average time to run a race is 14 minutes. You wish to see if...
1. The average time to run a race is 14 minutes. You wish to see
if a new training regimen will lower the time to run the race.
After doing the training regimen you run the race 35 times and the
average time to run the race now is 13.32 minutes with a standard
deviation of 1.4 minutes.
a) At the .05 level did the training regimen lower the time
(note: p value from computer is p = .003)
b)...
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5.)
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If one randomly selected runner is timed, find the...
The average time to run the 5K fun run is 20 minutes and the standard deviation...
The average time to run the 5K fun run is 20 minutes and the
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score of boys and girls on the math SOL. A random sample of 195
boys had an average score of 444.34 with a standard deviation of
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