In: Math
complete a between-subjects analysis of variance (ANOVA) by hand for the data:
ANOVA data:
A: 3, 1, 3, 4, 2
B: 4, 5, 4, 8, 7
C: 2, 3, 2, 4, 1
| 
 A:  | 
 B:  | 
 C:  | 
||
| 
 3  | 
 4  | 
 2  | 
||
| 
 1  | 
 5  | 
 3  | 
||
| 
 3  | 
 4  | 
 2  | 
||
| 
 4  | 
 8  | 
 4  | 
||
| 
 2  | 
 7  | 
 1  | 
 Total  | 
|
| 
 sum  | 
 13  | 
 28  | 
 12  | 
 53  | 
| 
 sum of square  | 
 39  | 
 170  | 
 34  | 
 243  | 

H1: At least one of the mean is different from the others

n1=n2=n3=5, N=15
T1, T2 , T3 are group totals

=
=55.7333


SSE= SST-SSG = 55.7333-32.1333 =23.6
Df for groups = 3-1=2
Df for total 15-1=14
Df for error = 14-2=12
| 
 ANOVA table  | 
||||
| 
 Source  | 
 SS  | 
 df  | 
 MS  | 
 F  | 
| 
 group  | 
 32.1333  | 
 2  | 
 32.1333/2=16.0667  | 
 16.0667/1.9667 = 8.1695  | 
| 
 Error  | 
 23.6000  | 
 12  | 
 23.6/12=1.9667  | 
|
| 
 Total  | 
 55.7333  | 
 14  | 
Let level of significance=0.05
Table value of F with (DF1=2, DF2=12 ) at 0.05 level =3.89
Calculated F=8.1695 > 3.89 the table value
The null hypothesis is rejected.
The data indicate there is a significant difference among the three groups