In: Math
complete a between-subjects analysis of variance (ANOVA) by hand for the data:
ANOVA data:
A: 3, 1, 3, 4, 2
B: 4, 5, 4, 8, 7
C: 2, 3, 2, 4, 1
A: |
B: |
C: |
||
3 |
4 |
2 |
||
1 |
5 |
3 |
||
3 |
4 |
2 |
||
4 |
8 |
4 |
||
2 |
7 |
1 |
Total |
|
sum |
13 |
28 |
12 |
53 |
sum of square |
39 |
170 |
34 |
243 |
H1: At least one of the mean is different from the others
n1=n2=n3=5, N=15
T1, T2 , T3 are group totals
=
=55.7333
SSE= SST-SSG = 55.7333-32.1333 =23.6
Df for groups = 3-1=2
Df for total 15-1=14
Df for error = 14-2=12
ANOVA table |
||||
Source |
SS |
df |
MS |
F |
group |
32.1333 |
2 |
32.1333/2=16.0667 |
16.0667/1.9667 = 8.1695 |
Error |
23.6000 |
12 |
23.6/12=1.9667 |
|
Total |
55.7333 |
14 |
Let level of significance=0.05
Table value of F with (DF1=2, DF2=12 ) at 0.05 level =3.89
Calculated F=8.1695 > 3.89 the table value
The null hypothesis is rejected.
The data indicate there is a significant difference among the three groups