A 25.0025.00 mL solution of 0.031500.03150 M Na2CO3Na2CO3 is titrated with 0.027600.02760 M Ba(NO3)2Ba(NO3)2. Calculate pBa2+pBa2+...

A 25.0025.00 mL solution of 0.031500.03150 M Na2CO3Na2CO3 is titrated with 0.027600.02760 M Ba(NO3)2Ba(NO3)2. Calculate pBa2+pBa2+ following the addition of the given volumes of Ba(NO3)2Ba(NO3)2. The ?spKsp for BaCO3BaCO3 is 5.0×10−9

11.80mL pBa2+ =__________________________

Ve pBa2+ =_________________________________

36.00 mL pBa2+=_______________________

Expert Solution

queen_honey_blossom answered 2 years ago

determine the molar solubility of Ba(IO3)2 in 0.02000 M Ba(NO3)2 solution.

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