Question

In: Math

In a recent Super Bowl, a TV network predicted that 87 % of the audience would...

In a recent Super Bowl, a TV network predicted that 87 % of the audience would express an interest in seeing one of its forthcoming television shows. The network ran commercials for these shows during the Super Bowl. The day after the Super Bowl, and Advertising Group sampled 44 people who saw the commercials and found that 39 of them said they would watch one of the television shows.

Suppose you are have the following null and alternative hypotheses for a test you are running:

H0:p=0.87H0:p=0.87
Ha:p≠0.87Ha:p≠0.87

Calculate the test statistic, rounded to 3 decimal places

z=z=

Solutions

Expert Solution

From the given data

Thus we conclude that the proportion of the audience would express an interest in seeing one of its forthcoming television show is 87 %

Answer: Z value = 0.323


Related Solutions

In a recent Super Bowl, a TV network predicted that 39 % of the audience would...
In a recent Super Bowl, a TV network predicted that 39 % of the audience would express an interest in seeing one of its forthcoming television shows. The network ran commercials for these shows during the Super Bowl. The day after the Super Bowl, and Advertising Group sampled 105 people who saw the commercials and found that 40 of them said they would watch one of the television shows. Suppose you are have the following null and alternative hypotheses for...
n a recent Super Bowl, a TV network predicted that 33 % of the audience would...
n a recent Super Bowl, a TV network predicted that 33 % of the audience would express an interest in seeing one of its forthcoming television shows. The network ran commercials for these shows during the Super Bowl. The day after the Super Bowl, and Advertising Group sampled 123 people who saw the commercials and found that 37 of them said they would watch one of the television shows. Suppose you are have the following null and alternative hypotheses for...
Suppose the Super Bowl is this week, and Carlos is in need of a television to...
Suppose the Super Bowl is this week, and Carlos is in need of a television to watch the big game. As a college student, Carlos knows that he can either buy his flat-screen television at the local electronics store, or he can shop online for a better deal but have to wait four days for the television to arrive. The following problem uses the economic concept of rate of time preference to help determine which decision is better for Carlos....
For a certain group of individuals, the average cost of a trip to the Super Bowl...
For a certain group of individuals, the average cost of a trip to the Super Bowl was $75. The standard deviation of the population was $50. This year, 49 fans who scheduled the trip paid an average of $89 for the three-day trip. Test the claim that the average cost is greater than last year’s cost at 1% significance level?
Based on the concept of elasticity, if the Super Bowl is played in Mile High Stadium,...
Based on the concept of elasticity, if the Super Bowl is played in Mile High Stadium, with a maximum seating of 74,000 seats, who would pay the seating tax of $5/seat? Question 4 options: The seller. The seller would pay part of it, the buyers pay the rest. The City of Denver. The buyers.
The Super Bowl Indicator Theory suggests that the stock market will have a positive year if...
The Super Bowl Indicator Theory suggests that the stock market will have a positive year if the team in the National Football Conference, or a team with an NFC origin, wins. If the American Football Conference team wins, the market will fall. According to the recent news (MarketWatch, 2/6/2017), it has accurately predicted the direction of the market for the year following 40 of the 50 Super Bowls since the first super bowl in 1967. Why do we have such...
In a television network, a survey of 2,500 people was made to know the audience of...
In a television network, a survey of 2,500 people was made to know the audience of a debate and from a movie that aired at different times: 2,100 watched the movie, 1,500 watched the debate and 350 They didn't watch either program. If we randomly choose one of the respondents: a) What is the probability that I saw the movie and the debate? b) What is the probability that he saw the movie, knowing that he did not see the...
TV advertising agencies face increasing challenges in reaching audience members because viewing TV programs via digital...
TV advertising agencies face increasing challenges in reaching audience members because viewing TV programs via digital streaming is gaining in popularity. A poll reported that 58% of 2341 American adults surveyed said they have watched digitally streamed TV programming on some type of device. (a) Calculate and interpret a confidence interval at the 99% confidence level for the proportion of all adult Americans who watched streamed programming up to that point in time. (Round your answers to three decimal places.)...
TV advertising agencies face increasing challenges in reaching audience members because viewing TV programs via digital...
TV advertising agencies face increasing challenges in reaching audience members because viewing TV programs via digital streaming is gaining in popularity. A poll reported that 56% of 2343 American adults surveyed said they have watched digitally streamed TV programming on some type of device. (a) Calculate and interpret a confidence interval at the 99% confidence level for the proportion of all adult Americans who watched streamed programming up to that point in time. (Round your answers to three decimal places.)...
TV advertising agencies face growing challenges in reaching audience members because viewing TV programsvia digital streaming...
TV advertising agencies face growing challenges in reaching audience members because viewing TV programsvia digital streaming is increasingly popular. The Harris poll reported on November 13, 2012 that 53% of2343 American adults surveyed said they have watched digitally streamed TV programming on some typeof device. a) What is the distribution of the sample proportion for this scenario? Justify your answer. b) Calculate and interpret a confidence interval at the 90% confidence level for the proportion of all adultAmericans who have...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT