In a recent Super Bowl, a TV network predicted that 87 % of the audience would...

In a recent Super Bowl, a TV network predicted that 87 % of the audience would express an interest in seeing one of its forthcoming television shows. The network ran commercials for these shows during the Super Bowl. The day after the Super Bowl, and Advertising Group sampled 44 people who saw the commercials and found that 39 of them said they would watch one of the television shows.

Suppose you are have the following null and alternative hypotheses for a test you are running:

H0:p=0.87H0:p=0.87
Ha:p≠0.87Ha:p≠0.87

Calculate the test statistic, rounded to 3 decimal places

z=z=

Expert Solution

From the given data

Thus we conclude that the proportion of the audience would express an interest in seeing one of its forthcoming television show is 87 %

Answer: Z value = 0.323

milcah answered 1 year ago

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